Question Number 7399 by Tawakalitu. last updated on 27/Aug/16 $${In}\:{an}\:{AP}\:,\:{if}\:{the}\:{m}^{{th}} \:{term}\:{is}\:{n}\:{and}\:{the}\:{n}^{{th}} \:{term} \\ $$$${is}\:{m}.\:{where}\:{m}\:{is}\:{not}\:{equal}\:{to}\:{n}.\:{find} \\ $$$$\left(\mathrm{1}\right)\:{The}\:{value}\:{of}\:\left({m}\:+\:{n}\right)^{{th}} \:{term} \\ $$$$\left(\mathrm{2}\right)\:{The}\:{p}^{{th}} \:{term}. \\ $$ Answered by Yozzia…
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Question Number 7263 by Tawakalitu. last updated on 19/Aug/16 Commented by Rasheed Soomro last updated on 20/Aug/16 $${I}\:{have}\:{answered}\:{your}\:{question}#\mathrm{6852} \\ $$$${which}\:{is}\:{very}\:{resembling}\:{to}\:{this}\:{question}. \\ $$$${Please}\:{see}\:{if}\:{you}\:{have}\:{not}\:{seen}\:{yet}. \\ $$ Commented…
Question Number 138320 by aliibrahim1 last updated on 12/Apr/21 Answered by Rasheed.Sindhi last updated on 17/Apr/21 $$\mathrm{11}^{{n}} =\left(\mathrm{1}+\mathrm{10}\right)^{{n}} =\begin{pmatrix}{{n}}\\{\mathrm{0}}\end{pmatrix}\left(\mathrm{10}\right)^{\mathrm{0}} +\begin{pmatrix}{{n}}\\{\mathrm{1}}\end{pmatrix}\left(\mathrm{10}\right)^{\mathrm{1}} \\ $$$$\:\:\:\:\:\:\:+\begin{pmatrix}{{n}}\\{\mathrm{2}}\end{pmatrix}\left(\mathrm{10}\right)^{\mathrm{2}} +\underset{{divisible}\:{by}\:\mathrm{1000}} {\underbrace{\begin{pmatrix}{{n}}\\{\mathrm{3}}\end{pmatrix}\left(\mathrm{10}\right)^{\mathrm{3}} ….+\begin{pmatrix}{{n}}\\{{n}}\end{pmatrix}\left(\mathrm{10}\right)^{{n}}…
Question Number 7246 by Tawakalitu. last updated on 18/Aug/16 Answered by Yozzia last updated on 19/Aug/16 $${Define}\:{the}\:{number}\:{k}\:{such}\:{that}\: \\ $$$${k}={x}^{{n}+\mathrm{3}} +{y}^{{n}+\mathrm{3}} +{z}^{{n}+\mathrm{3}} −{xyz}\left({x}^{{n}} +{y}^{{n}} +{z}^{{n}} \right)…
Question Number 7227 by FilupSmith last updated on 17/Aug/16 $${S}=\underset{{t}=\mathrm{1}} {\overset{{n}} {\sum}}\left(−\mathrm{1}\right)^{{t}} {t}^{{k}} {k}^{−{n}} ,\:{k}>\mathrm{1} \\ $$$$\mathrm{Solve}\:\mathrm{for}\:{S} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 138295 by greg_ed last updated on 12/Apr/21 $$\boldsymbol{\mathrm{hi}}\:! \\ $$$$\boldsymbol{\mathrm{Simplify}}\::\:{for}\:{n}\:\in\:\mathbb{N}^{\ast} ,\:\:{S}_{{n}} \:=\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\:\:\frac{\mathrm{3}{k}+\mathrm{8}}{{k}\left({k}+\mathrm{2}\right)\mathrm{2}^{{k}} }\:. \\ $$ Answered by mr W last updated…
Question Number 7211 by Tawakalitu. last updated on 16/Aug/16 $${Find}\:{the}\:{next}\:{time}\:{of}\:{the}\:{sequence}\: \\ $$$$−\mathrm{1},\:\mathrm{8},\:\mathrm{49},\:\mathrm{68},\:\mathrm{131},\:….. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 7163 by Tawakalitu. last updated on 14/Aug/16 Commented by sou1618 last updated on 14/Aug/16 $$\underset{{a}=\mathrm{1}} {\overset{\mathrm{4}} {\sum}}\left(\underset{{b}=\mathrm{0}} {\overset{\mathrm{4}} {\sum}}{a}^{{b}} \right)=\underset{{a}=\mathrm{1}} {\overset{\mathrm{4}} {\sum}}\left({a}^{\mathrm{0}} +{a}^{\mathrm{1}}…