Menu Close

Category: Arithmetic

is-it-possible-to-prove-that-mn-m-n-m-n-divisible-by-6-always-

Question Number 223414 by BaliramKumar last updated on 24/Jul/25 $${is}\:{it}\:{possible}\:{to}\:{prove}\:{that}\:{mn}\left({m}+{n}\right)\left({m}−{n}\right)\: \\ $$$${divisible}\:{by}\:\mathrm{6}\:{always}\:\:\:\:\:\:\:\:\:\: \\ $$ Answered by mehdee7396 last updated on 24/Jul/25 $${let}\:\:\:{d}={mn}\left({m}+{n}\right)\left({m}−{n}\right) \\ $$$${case}\mathrm{1} \\…

Determine-gcd-13a-19b-ab-given-that-gcd-a-19-gcd-b-13-1-

Question Number 223348 by cryptograph last updated on 21/Jul/25 $${Determine}\:{gcd}\left(\mathrm{13}{a}+\mathrm{19}{b},{ab}\right)\:{given}\:{that}\:{gcd}\left({a},\mathrm{19}\right)={gcd}\left({b},\mathrm{13}\right)=\mathrm{1} \\ $$ Commented by A5T last updated on 23/Jul/25 $$\mathrm{This}\:\mathrm{isn}'\mathrm{t}\:\mathrm{unique}.\:\mathrm{a}=\mathrm{1}\:\mathrm{and}\:\mathrm{b}=\mathrm{1}\Rightarrow\:\mathrm{gcd}\left(\mathrm{32},\mathrm{1}\right)=\mathrm{1} \\ $$$$\mathrm{a}=\mathrm{2}\:\mathrm{and}\:\mathrm{b}=\mathrm{2}\:\Rightarrow\:\mathrm{gcd}\left(\mathrm{64},\mathrm{4}\right)=\mathrm{4} \\ $$ Answered…

Question-223125

Question Number 223125 by BaliramKumar last updated on 15/Jul/25 Answered by mr W last updated on 16/Jul/25 $${A}\:{needs}\:\mathrm{85}{s}\:{for}\:{one}\:{round}, \\ $$$${B}\:{needs}\:\mathrm{45}{s}\:{for}\:{one}\:{round}. \\ $$$${case}\:\mathrm{1}:\:{they}\:{run}\:{in}\:{opposite}\:{directions} \\ $$$${say}\:{they}\:{meet}\:{after}\:{time}\:{t}\:{for}\:{the} \\…

Question-222736

Question Number 222736 by Lekhraj last updated on 06/Jul/25 Answered by Raphael254 last updated on 08/Sep/25 $$\begin{array}{|c|c|}{\boldsymbol{{To}}\:\boldsymbol{{a}}\:\boldsymbol{{number}}\:\boldsymbol{{be}}\:\boldsymbol{{divisible}}\:\boldsymbol{{by}}\:\mathrm{33},}\\{\boldsymbol{{it}}\:\boldsymbol{{needs}}\:\boldsymbol{{to}}\:\boldsymbol{{be}}\:\boldsymbol{{divisible}}\:\boldsymbol{{by}}\:\mathrm{3}\:\boldsymbol{{and}}\:\mathrm{11}}\\\hline\end{array} \\ $$$$ \\ $$$${Why}? \\ $$$$ \\ $$$${ab}\mid{n}\:\Rightarrow\:{a}\mid{n}\:{and}\:{b}\mid{n}…

Prove-that-a-b-a-c-a-d-b-c-b-d-c-d-divisible-by-12-with-a-b-c-d-Z-

Question Number 222352 by cryptograph last updated on 23/Jun/25 $${Prove}\:{that}\::\:\left({a}−{b}\right)\left({a}−{c}\right)\left({a}−{d}\right)\left({b}−{c}\right)\left({b}−{d}\right)\left({c}−{d}\right)\:{divisible}\:{by}\:\mathrm{12},\:{with}\:{a},{b},{c},{d}\:\in\mathbb{Z} \\ $$ Answered by vnm last updated on 23/Jun/25 $$\mathrm{Among}\:\mathrm{four}\:\mathrm{integers}\:\mathrm{there}\:\mathrm{will}\:\mathrm{always}\:\mathrm{be}\:\mathrm{two}\: \\ $$$$\mathrm{that}\:\mathrm{are}\:\mathrm{comparable}\:\mathrm{modulo}\:\mathrm{3}\: \\ $$$$\mathrm{and}\:\mathrm{two}\:\mathrm{pairs}\:\mathrm{or}\:\mathrm{three}\:\mathrm{that}\:\mathrm{are} \\…