Question Number 54765 by peter frank last updated on 10/Feb/19 Answered by tanmay.chaudhury50@gmail.com last updated on 10/Feb/19 $$\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{2}\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {sin}^{\mathrm{2}×\mathrm{24}−\mathrm{1}} {xcos}^{\mathrm{2}×\mathrm{27}−\mathrm{1}} {xdx} \\ $$$${formula}\:\mathrm{2}\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}}…
Question Number 185805 by Rupesh123 last updated on 27/Jan/23 Answered by MJS_new last updated on 28/Jan/23 $$\left(\mathrm{2}+\sqrt{\mathrm{3}}\right)^{\mathrm{2023}} ={x} \\ $$$$\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}×\frac{{x}^{\mathrm{2}} +{x}^{−\mathrm{2}} +\mathrm{1}}{{x}+{x}^{+\mathrm{1}} }=\frac{\mathrm{1}+{n}^{\mathrm{2}} }{{n}}\:\Rightarrow\:{n}=\left(\frac{\sqrt{\mathrm{3}}{x}}{{x}^{\mathrm{2}} −\mathrm{1}}\right)^{\pm\mathrm{1}}…
Question Number 185782 by Rupesh123 last updated on 27/Jan/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 120241 by olalekanoriyomi last updated on 30/Oct/20 $$\boldsymbol{\mathrm{C}}{orrection}\:\boldsymbol{{to}}\:\boldsymbol{{the}}\:\boldsymbol{{last}}\:\boldsymbol{{assignment}} \\ $$$$ \\ $$$$\left(\mathrm{1}\right)\frac{\mathrm{1}}{\mathrm{81}^{\boldsymbol{{x}}−\mathrm{2}} }\:=\:\mathrm{27}^{\mathrm{1}−\boldsymbol{{x}}} \\ $$$$\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{4}\left(\boldsymbol{{x}}−\mathrm{2}\right)} }=\mathrm{3}^{\mathrm{3}\left(\mathrm{1}−\boldsymbol{{x}}\right)} \\ $$$$\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{4}\boldsymbol{{x}}−\mathrm{8}} }=\mathrm{3}^{\mathrm{3}−\mathrm{3}\boldsymbol{{x}}} \\ $$$$\mathrm{3}^{−\mathrm{4}\boldsymbol{{x}}+\mathrm{8}} =\mathrm{3}^{\mathrm{3}−\mathrm{3}\boldsymbol{{x}}} \\…
Question Number 54700 by peter frank last updated on 09/Feb/19 $$\mathrm{F}{i}\mathrm{nd}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{to}\:\mathrm{infinity} \\ $$$$\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}\:}\mathrm{cos}\:\theta+\frac{\mathrm{1}}{\mathrm{4}}\mathrm{cos}\:\mathrm{2}\theta−\frac{\mathrm{1}}{\mathrm{8}}\mathrm{cos}\:\mathrm{3}\theta+………. \\ $$$$ \\ $$ Commented by maxmathsup by imad last updated on…
Question Number 185743 by Rupesh123 last updated on 26/Jan/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 119928 by peter frank last updated on 28/Oct/20 Answered by bramlexs22 last updated on 28/Oct/20 $${mx}\:=\:{y}−\left(\frac{\mathrm{3}{m}^{\mathrm{2}} +\mathrm{4}}{\mathrm{4}{m}}\right) \\ $$$$\:{x}\:=\:\frac{{y}}{{m}}−\left(\frac{\mathrm{3}{m}^{\mathrm{2}} +\mathrm{4}}{\mathrm{4}{m}^{\mathrm{2}} }\right)\:\leftarrow{substitute} \\ $$$${to}\:{quadratic}\:{function}\:{give}…
Question Number 54322 by peter frank last updated on 02/Feb/19 Answered by kaivan.ahmadi last updated on 02/Feb/19 $$\mathrm{ax}+\mathrm{by}=\mathrm{c}\:\mathrm{and}\:\mathrm{bx}−\mathrm{ay}=\mathrm{d}\:\mathrm{are}\:\mathrm{perpendicular} \\ $$$$\mathrm{abx}^{\mathrm{2}} +\left(\mathrm{b}^{\mathrm{2}} −\mathrm{a}^{\mathrm{2}} \right)\mathrm{xy}−\mathrm{aby}^{\mathrm{2}} =\mathrm{cd} \\…
Question Number 185386 by Rupesh123 last updated on 20/Jan/23 Commented by floor(10²Eta[1]) last updated on 21/Jan/23 $$\mathrm{a}^{\mathrm{2}} +\mathrm{2ab}+\mathrm{b}^{\mathrm{2}} +\mathrm{1990a}+\mathrm{1990b}+\mathrm{36}= \\ $$$$=\mathrm{a}^{\mathrm{2}} +\mathrm{1990a}+\mathrm{36}+\mathrm{b}^{\mathrm{2}} +\mathrm{1990b}+\mathrm{36} \\ $$$$\Rightarrow\mathrm{2ab}=\mathrm{36}\Rightarrow\mathrm{ab}=\mathrm{18}…
Question Number 185269 by Rupesh123 last updated on 19/Jan/23 Answered by aleks041103 last updated on 19/Jan/23 $${p}=\sqrt{{n}−\mathrm{8}}+\sqrt{{n}+\mathrm{8}}\Rightarrow{n}\geqslant\mathrm{8} \\ $$$${p}^{\mathrm{2}} =\mathrm{2}{n}−\mathrm{2}\sqrt{{n}^{\mathrm{2}} −\mathrm{64}} \\ $$$$\Rightarrow\sqrt{\mathrm{4}\left({n}^{\mathrm{2}} −\mathrm{64}\right)}=\mathrm{2}{n}−{p}^{\mathrm{2}} \\…