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Category: Arithmetic

Question-172999

Question Number 172999 by Mikenice last updated on 04/Jul/22 Answered by MikeH last updated on 05/Jul/22 $$\mathrm{2}{S}\:=\:{n}\left[\mathrm{2}{a}\:+\:{nd}−{d}\right] \\ $$$$\Rightarrow\:\mathrm{2}{S}\:=\:\mathrm{2}{an}\:+\:{n}^{\mathrm{2}} {d}\:−\:{dn} \\ $$$$\Rightarrow\:{n}^{\mathrm{2}} {d}\:+\:\left(\mathrm{2}{a}−{d}\right){n}−\mathrm{2}{S}\:=\:\mathrm{0} \\ $$$${n}\:=\:\frac{\left({d}−\mathrm{2}{a}\right)\pm\sqrt{\left(\mathrm{2}{a}−{d}\right)^{\mathrm{2}}…

lim-x-n-ln-1-n-find-the-limit-

Question Number 41855 by 123456780 last updated on 14/Aug/18 $$\underset{{x}\rightarrow+\infty\:\:} {\mathrm{lim}}\frac{\mathrm{n}!}{\mathrm{ln}\:\left(\mathrm{1}+\mathrm{n}!\right)} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{limit} \\ $$ Commented by prof Abdo imad last updated on 14/Aug/18 $${let}\:{put}\:{p}={n}!\:\Rightarrow\:\:\frac{{n}!}{{ln}\left(\mathrm{1}+{n}!\right)}\:=\frac{{p}}{{ln}\left(\mathrm{1}+{p}\right)}…

show-that-U-n-1-nx-n-n-1-2-x-2-n-n-1-n-2-3-x-3-for-which-U-n-1-x-n-

Question Number 41721 by Rio Michael last updated on 11/Aug/18 $${show}\:{that} \\ $$$${U}_{{n}} =\:\mathrm{1}+\:{nx}\:+\:\frac{{n}\left({n}−\mathrm{1}\right)}{\mathrm{2}!}\:{x}^{\mathrm{2}\:\:} +\:\frac{{n}\left({n}−\mathrm{1}\right)\left({n}−\mathrm{2}\right)}{\mathrm{3}!}{x}^{\mathrm{3}} +\:…. \\ $$$${for}\:{which}\:{U}_{{n}} =\:\left(\mathrm{1}\:+\:{x}\right)^{{n}} . \\ $$ Commented by maxmathsup…