Question Number 226336 by Spillover last updated on 25/Nov/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 226337 by Spillover last updated on 25/Nov/25 Answered by mr W last updated on 26/Nov/25 Commented by mr W last updated on 26/Nov/25…
Question Number 226338 by Spillover last updated on 25/Nov/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 225716 by ajfour last updated on 07/Nov/25 Commented by ajfour last updated on 07/Nov/25 $${Find}\:{radius}\:{of}\:{blue}\:{circle}\:{R}. \\ $$ Commented by fantastic last updated on…
Question Number 225497 by gregori last updated on 31/Oct/25 Answered by Simurdiera last updated on 01/Nov/25 $$\begin{array}{|c|}{\mathrm{11}}\\\hline\end{array}\begin{cases}{{x}\:+\:{y}\:+\:\sqrt{{xy}}\:=\:\mathrm{28}\:\:\:\:\:\ldots\left(\mathrm{I}\right)}\\{{x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \:+\:{xy}\:=\:\mathrm{336}\:\:\:\:\:\ldots\left(\mathrm{II}\right)}\end{cases} \\ $$$$\mathrm{En}\:\left(\mathrm{II}\right),\:\mathrm{sumando}\:\mathrm{ceros} \\ $$$${x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \:+\:{xy}\:+\:{xy}\:−\:{xy}\:=\:\mathrm{336}…
Question Number 225449 by efronzo1 last updated on 26/Oct/25 Answered by fantastic last updated on 26/Oct/25 Commented by fantastic last updated on 26/Oct/25 $$ \\…
Question Number 224702 by gregori last updated on 28/Sep/25 Commented by gregori last updated on 28/Sep/25 $$\:\:\:\underbrace{ } \\ $$ Answered by mehdee7396 last updated…
Question Number 222531 by BHOOPENDRA last updated on 29/Jun/25 $${The}\:{foot}\:{of}\:{the}\:{perpendicular}\:{from}\: \\ $$$${a}\:{point}\:{of}\:{the}\:{circle}\:\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{1},{z}=\mathrm{0} \\ $$$${to}\:{the}\:{plan}\:\mathrm{2}{x}+\mathrm{3}{y}+{z}=\mathrm{6}\:{lie}\:{on}\:{curve}−−−−−− \\ $$ Answered by mr W last updated on…
Question Number 221288 by alcohol last updated on 29/May/25 Answered by mahdipoor last updated on 29/May/25 $$\frac{{x}+\frac{{x}+…}{\mathrm{1}+…}}{\mathrm{1}+\frac{{x}+…}{\mathrm{1}+…}}={A}=\frac{{x}+{A}}{\mathrm{1}+{A}}\:\Rightarrow{A}=\sqrt{{x}} \\ $$$$\int\sqrt{{x}}{dx}=\frac{\mathrm{2}}{\mathrm{3}}{x}^{\mathrm{3}/\mathrm{2}} +{C} \\ $$$$ \\ $$ Terms…
Question Number 221271 by gregori last updated on 29/May/25 $$\:\:{Find}\:{the}\:{remainder}\:{when}\:{x}^{\mathrm{100}} \: \\ $$$$\:\:{is}\:{divided}\:{by}\:\left({x}^{\mathrm{2}} +{x}+\mathrm{1}\right) \\ $$ Answered by A5T last updated on 29/May/25 $$\mathrm{x}^{\mathrm{2}} \equiv\left(−\mathrm{1}−\mathrm{x}\right)\left(\mathrm{mod}\:\:\mathrm{x}^{\mathrm{2}}…