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Category: Coordinate Geometry

lim-x-0-1-cosxcos2x-cos-nx-x-2-n-n-1-2n-1-12-

Question Number 197359 by sniper237 last updated on 14/Sep/23 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\frac{\mathrm{1}−{cosxcos}\mathrm{2}{x}…{cos}\left({nx}\right)}{{x}^{\mathrm{2}} }\:=\:\frac{{n}\left({n}+\mathrm{1}\right)\left(\mathrm{2}{n}+\mathrm{1}\right)}{\mathrm{12}}\: \\ $$ Commented by universe last updated on 16/Sep/23 Answered by witcher3 last…

If-A-a-2-2a-B-1-a-2-2-a-and-S-1-0-are-three-points-then-prove-that-1-SA-1-SB-1-

Question Number 196992 by MATHEMATICSAM last updated on 05/Sep/23 $$\mathrm{If}\:\mathrm{A}\left({a}^{\mathrm{2}} ,\:\mathrm{2}{a}\right),\:\mathrm{B}\left(\frac{\mathrm{1}}{{a}^{\mathrm{2}} },\:\frac{−\:\mathrm{2}}{{a}}\right)\:\mathrm{and}\:\mathrm{S}\left(\mathrm{1},\:\mathrm{0}\right)\: \\ $$$$\mathrm{are}\:\mathrm{three}\:\mathrm{points}\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that}, \\ $$$$\frac{\mathrm{1}}{\mathrm{SA}}\:+\:\frac{\mathrm{1}}{\mathrm{SB}}\:=\:\mathrm{1}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

prove-that-lim-n-1-n-1-p-2-n-1-p-pln-p-1-p-1-ln-pi-

Question Number 196674 by Erico last updated on 29/Aug/23 $$\mathrm{prove}\:\mathrm{that}\: \\ $$$$\underset{\mathrm{n}\rightarrow+\infty} {\mathrm{lim}}\:\left(−\mathrm{1}\right)^{\mathrm{n}−\mathrm{1}} +\underset{\mathrm{p}=\mathrm{2}} {\overset{\mathrm{n}} {\sum}}\left(−\mathrm{1}\right)^{\mathrm{p}} \mathrm{pln}\left(\frac{\mathrm{p}+\mathrm{1}}{\mathrm{p}−\mathrm{1}}\right)=\mathrm{ln}\left(\pi\right) \\ $$ Terms of Service Privacy Policy Contact:…

Question-196304

Question Number 196304 by cortano12 last updated on 22/Aug/23 Answered by a.lgnaoui last updated on 24/Aug/23 $$\:\boldsymbol{\mathrm{S}}=\mathrm{shaded}\:\mathrm{Area} \\ $$$$\boldsymbol{\mathrm{S}}\mathrm{1}=\mathrm{Arc}\left(\mathrm{AMC}\right)\:\:\:\boldsymbol{\mathrm{S}}\mathrm{2}=\mathrm{Arc}\left(\mathrm{OBD}\right) \\ $$$$\:\boldsymbol{\mathrm{S}}=\boldsymbol{\mathrm{S}}\left(\boldsymbol{\mathrm{ABCD}}\right)−\boldsymbol{\mathrm{S}}\mathrm{1}+\boldsymbol{\mathrm{S}}\mathrm{2} \\ $$$$\bullet\boldsymbol{\mathrm{Calcul}}\:\boldsymbol{\mathrm{de}}\:\boldsymbol{\mathrm{S}}\left(\mathrm{ABCD}\right) \\ $$$$\:\:\mathrm{OBsin}\:\mathrm{30}=\mathrm{OAsin}\:\mathrm{45}\Rightarrow\:\:\boldsymbol{\mathrm{OA}}=\mathrm{5}\sqrt{\mathrm{2}}\:…

lim-n-sin-2pi-n-2-1-0-lim-n-arg-n-2-n-1-i-0-

Question Number 196321 by sniper237 last updated on 22/Aug/23 $$\:\:\:\underset{{n}\rightarrow+\infty} {\mathrm{lim}}\:{sin}\left(\mathrm{2}\pi\sqrt{{n}^{\mathrm{2}} +\mathrm{1}\:}\:\right)\:=\:\mathrm{0} \\ $$$$\:\:\:\:\underset{{n}\rightarrow+\infty} {\mathrm{lim}}\:\:{arg}\left({n}^{\mathrm{2}} +{n}+\mathrm{1}+{i}\right)\:=\:\mathrm{0} \\ $$ Answered by witcher3 last updated on 22/Aug/23…

M-a-inside-poin-in-ABC-M-bar-A-area-MBC-B-area-MAC-C-area-MAB-

Question Number 194821 by sniper237 last updated on 16/Jul/23 $${M}\:{a}\:{inside}\:{poin}\:{in}\:\:\Delta{ABC}. \\ $$$${M}\:=\:{bar}\:\left\{\left({A},\:{area}\left({MBC}\right)\right),\:\left({B},\:{area}\left({MAC}\right)\right),\left({C},{area}\left({MAB}\right)\right)\right\} \\ $$ Commented by mr W last updated on 16/Jul/23 $${what}\:{do}\:{mean}\:{with}\:\left({A},\:{area}\left({MBC}\right)\right)? \\ $$$${what}\:{do}\:{mean}\:{with}\:{bar}\:\left\{{X},\:{Y},\:{Z}\right\}?…

Resolution-de-l-exercice-du-28-6-23-envoye-par-universe-Q194116-

Question Number 194301 by a.lgnaoui last updated on 02/Jul/23 $$\boldsymbol{\mathrm{Resolution}}\:\boldsymbol{\mathrm{de}}\:\boldsymbol{\mathrm{l}}\:\boldsymbol{\mathrm{exercice}}\:\boldsymbol{\mathrm{du}}\:\mathrm{28}.\mathrm{6}.\mathrm{23} \\ $$$$\:\:\left({env}\mathrm{o}{ye}\:{par}\:{universe}\:\right) \\ $$$$\boldsymbol{{Q}}\mathrm{194116} \\ $$$$ \\ $$ Answered by a.lgnaoui last updated on 02/Jul/23…