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Category: Coordinate Geometry

Question-193235

Question Number 193235 by mathlove last updated on 08/Jun/23 Answered by a.lgnaoui last updated on 08/Jun/23 $$\boldsymbol{\mathrm{T}}\mathrm{otale}\:\mathrm{Area}=\mathrm{22}+\mathrm{A}\:\:\:\:\:\:\left(\mathrm{A}=\boldsymbol{\mathrm{xy}}\right) \\ $$$$\mathrm{22}+\boldsymbol{\mathrm{xy}}=\mathrm{6}\boldsymbol{\mathrm{x}}+\left(\mathrm{8}−\boldsymbol{\mathrm{x}}\right)\boldsymbol{\mathrm{y}} \\ $$$$\mathrm{2}\boldsymbol{\mathrm{xy}}=\mathrm{8}\boldsymbol{\mathrm{y}}+\mathrm{6}\boldsymbol{\mathrm{x}}−\mathrm{22} \\ $$$$ \\ $$$$\boldsymbol{\mathrm{xy}}=\mathrm{4}\boldsymbol{\mathrm{y}}+\mathrm{3}\boldsymbol{\mathrm{x}}−\mathrm{11}\:\:\:\left(\mathrm{1}\right)…

Question-65022

Question Number 65022 by ajfour last updated on 24/Jul/19 Commented by MJS last updated on 24/Jul/19 $$\mathrm{I}\:\mathrm{used}\:\mathrm{a}\:\mathrm{calculator}.\:\mathrm{I}'\mathrm{ve}\:\mathrm{got}\:\mathrm{an}\:\mathrm{old}\:\mathrm{TI}−\mathrm{89} \\ $$$$\mathrm{you}\:\mathrm{can}\:\mathrm{use}\:\mathrm{any}\:\mathrm{calculator}\:\mathrm{which}\:\mathrm{is}\:\mathrm{able}\:\mathrm{to} \\ $$$$\mathrm{approximately}\:\mathrm{solve}\:\mathrm{equations}\:\mathrm{and}\:\mathrm{integrals} \\ $$$$\mathrm{select}\:\mathrm{a}\:\mathrm{value}\:\mathrm{for}\:{r} \\ $$$$\mathrm{calculate}\:{P},\:{Q}\:\mathrm{and}\:\mathrm{the}\:\mathrm{integrals}…

Question-130263

Question Number 130263 by pete last updated on 23/Jan/21 Answered by Olaf last updated on 23/Jan/21 $$\mathrm{B}\begin{pmatrix}{{x}_{\mathrm{B}} \:=\:\mathrm{12}−\mathrm{2}{y}_{\mathrm{B}} \:=\:\mathrm{12}}\\{\mathrm{0}}\end{pmatrix} \\ $$$$\mathrm{E}\begin{pmatrix}{\mathrm{0}}\\{\frac{\mathrm{1}}{\mathrm{2}}\:=\:\frac{{y}_{\mathrm{E}} }{{x}_{\mathrm{B}} }\:\Rightarrow\:{y}_{\mathrm{E}} \:=\:\mathrm{6}}\end{pmatrix} \\…

Question-64709

Question Number 64709 by ajfour last updated on 20/Jul/19 Commented by ajfour last updated on 20/Jul/19 $${If}\:{regions}\:{A}\:{and}\:{B}\:{have}\:{the}\:{same} \\ $$$${area},\:{and}\:{both}\:{parabolas}\:{have} \\ $$$${the}\:{same}\:{shape}\:{but}\:{their}\:{axis}\:\bot\:{to} \\ $$$${each}\:{other},\:{then}\:{determine} \\ $$$${the}\:{equation}\:{of}\:{the}\:{red}\:{parabola}.…