Question Number 60812 by peter frank last updated on 26/May/19 Commented by tanmay last updated on 26/May/19 $${area}\:{of}\:{BCADB}=\mathrm{2}×\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{5}×\mathrm{12}=\mathrm{60} \\ $$$$\mathrm{60}=\mathrm{2}\left[\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{13}×{h}\right] \\ $$$${h}=\frac{\mathrm{60}}{\mathrm{13}} \\ $$$${sin}\theta_{\mathrm{1}} =\frac{{h}}{\mathrm{12}}\:\:\:{and}\:{sin}\theta_{\mathrm{2}}…
Question Number 60788 by ajfour last updated on 25/May/19 Commented by ajfour last updated on 25/May/19 $${In}\:{terms}\:{of}\:\alpha\:{and}\:{ellipse}\:{parameters} \\ $$$${a}\:{and}\:{b},\:{find}\:{maximum}\:{colored}\:{area}. \\ $$ Answered by mr W…
Question Number 126192 by ajfour last updated on 18/Dec/20 Commented by ajfour last updated on 18/Dec/20 $${If}\:{shape}\:{of}\:{parabola}\:{is}\:{same}\:{as} \\ $$$${that}\:{of}\:{y}={x}^{\mathrm{2}} ,\:{find}\:\:{radius}\:{of} \\ $$$${the}\:{smaller}\:{circle}. \\ $$ Commented…
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Question Number 191642 by a.lgnaoui last updated on 30/Apr/23 $$\mathrm{Comparer}\:\left[\mathrm{OHDF}\right]\:\:\mathrm{avec}\:\left[\mathrm{ABHEF}\right] \\ $$$$\left({avec}\:{preuve}\right) \\ $$$$\:\:{Sa}\mathrm{c}{h}\mathrm{a}{nt}\:{que}: \\ $$$$\mathrm{OH}\mid\mid\mathrm{DF}\:\:\:\mathrm{HE}=\mathrm{EF}\:\:\:\mathrm{OB}=\mathrm{4OA} \\ $$$$\:\:\:\mathrm{CH}=\mathrm{2BC}\:\mathrm{et}\:\mathrm{BC}<\mathrm{OB}.\:\:\: \\ $$$$ \\ $$ Commented by a.lgnaoui…
Question Number 191639 by a.lgnaoui last updated on 28/Apr/23 $$\mathrm{Une}\:\mathrm{feuille}\:\mathrm{de}\:\mathrm{papier}\:\mathrm{format}\:\boldsymbol{\mathrm{A}}\mathrm{4}\:\mathrm{est}\:\mathrm{plie} \\ $$$$\:\boldsymbol{\mathrm{n}}\:\mathrm{fois}\:\mathrm{simultanement}\:\mathrm{en}\:\mathrm{longueur}\:\mathrm{et} \\ $$$$\mathrm{largeur}\:\left(\mathrm{total}\:\mathrm{plie}=\mathrm{2n}\right) \\ $$$$−\mathrm{Quel}\:\mathrm{son}\:\mathrm{les}\:\mathrm{nouvelles}\:\mathrm{dimensions}\:\mathrm{de}\:\mathrm{cette}\:\mathrm{feuille} \\ $$$$\:\:\:\mathrm{la}\:\mathrm{feuille}\:\mathrm{a}\:\mathrm{la}\:\mathrm{fin}\:. \\ $$$$−\mathrm{quel}\:\mathrm{seront}\:\mathrm{ses}\:\mathrm{dimensions}\:\:\mathrm{apres}\: \\ $$$$\:\:\:\:\mathrm{6}\:\boldsymbol{\mathrm{pliages}} \\ $$$$−\mathrm{Quel}\:\mathrm{seront}\:\:\mathrm{les}\:\mathrm{dimensions}\:\mathrm{pour}\:\mathrm{une}\:\mathrm{feuille}\:\boldsymbol{\mathrm{care}}\:\mathrm{de}\:\mathrm{30}\:\boldsymbol{\mathrm{cm}}\: \\…
Question Number 60459 by tanmay last updated on 21/May/19 Commented by bhanukumarb2@gmail.com last updated on 21/May/19 $${source}\:{of}\:{question} \\ $$ Commented by tanmay last updated on…
Question Number 60439 by ajfour last updated on 21/May/19 Commented by ajfour last updated on 21/May/19 $$\mathrm{Find}\:\mathrm{length}\:\mathrm{AB}.\:\mathrm{The}\:\mathrm{curve}\:\mathrm{is}\:\mathrm{cubic}. \\ $$ Answered by tanmay last updated on…
Question Number 191364 by cortano12 last updated on 23/Apr/23 Commented by cortano12 last updated on 23/Apr/23 $$\mathrm{find}\:\mathrm{CD}. \\ $$ Commented by mr W last updated…
Question Number 125782 by ajfour last updated on 13/Dec/20 Commented by ajfour last updated on 13/Dec/20 $${Find}\:{radius}\:{of}\:{the}\:{smaller}\:{circle}. \\ $$ Commented by MJS_new last updated on…