Question Number 222531 by BHOOPENDRA last updated on 29/Jun/25 $${The}\:{foot}\:{of}\:{the}\:{perpendicular}\:{from}\: \\ $$$${a}\:{point}\:{of}\:{the}\:{circle}\:\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{1},{z}=\mathrm{0} \\ $$$${to}\:{the}\:{plan}\:\mathrm{2}{x}+\mathrm{3}{y}+{z}=\mathrm{6}\:{lie}\:{on}\:{curve}−−−−−− \\ $$ Answered by mr W last updated on…
Question Number 221288 by alcohol last updated on 29/May/25 Answered by mahdipoor last updated on 29/May/25 $$\frac{{x}+\frac{{x}+…}{\mathrm{1}+…}}{\mathrm{1}+\frac{{x}+…}{\mathrm{1}+…}}={A}=\frac{{x}+{A}}{\mathrm{1}+{A}}\:\Rightarrow{A}=\sqrt{{x}} \\ $$$$\int\sqrt{{x}}{dx}=\frac{\mathrm{2}}{\mathrm{3}}{x}^{\mathrm{3}/\mathrm{2}} +{C} \\ $$$$ \\ $$ Terms…
Question Number 221271 by gregori last updated on 29/May/25 $$\:\:{Find}\:{the}\:{remainder}\:{when}\:{x}^{\mathrm{100}} \: \\ $$$$\:\:{is}\:{divided}\:{by}\:\left({x}^{\mathrm{2}} +{x}+\mathrm{1}\right) \\ $$ Answered by A5T last updated on 29/May/25 $$\mathrm{x}^{\mathrm{2}} \equiv\left(−\mathrm{1}−\mathrm{x}\right)\left(\mathrm{mod}\:\:\mathrm{x}^{\mathrm{2}}…
Question Number 221184 by Lekhraj last updated on 26/May/25 Commented by mehdee7396 last updated on 26/May/25 $${A},{B}\:?\:{are}\:{thay}\:{focies} \\ $$ Commented by Lekhraj last updated on…
Question Number 221050 by MrGaster last updated on 23/May/25 Commented by MrGaster last updated on 23/May/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 220257 by abbb last updated on 10/May/25 $${proof}\:{that}\:{volume}\:{of}\:{frustum}\:{of} \\ $$$$\:{circular}\:{cone}\:{is}\:\frac{\mathrm{1}}{\mathrm{3}}{h}\left[{A}\mathrm{1}+{A}\mathrm{2}+\sqrt{{A}\mathrm{1}{A}\mathrm{2}}\right. \\ $$$${A}_{\mathrm{1}} {and}\:{A}_{\mathrm{2}} \:{are}\:\:{areas}\:{of}\:{base} \\ $$ Answered by MrGaster last updated on 10/May/25…
Question Number 219685 by alcohol last updated on 30/Apr/25 Answered by SdC355 last updated on 01/May/25 $$\kappa=\frac{\mathrm{2}}{\:\sqrt{\left(\mathrm{1}+\mathrm{4}{x}^{\mathrm{2}} \right)^{\mathrm{3}} }}\:\:\:\left(\mathrm{curvature}\:\kappa=\frac{\mid\mid{y}^{\left(\mathrm{2}\right)} \left({t}\right)\mid\mid}{\:\sqrt{\left(\mathrm{1}+\left({y}^{\left(\mathrm{1}\right)} \left({t}\right)\right)^{\mathrm{2}} \right)^{\mathrm{3}} }}\:\right) \\ $$$${r}=\frac{\mathrm{1}}{\kappa}=\frac{\sqrt{\left(\mathrm{1}+\mathrm{4}{x}^{\mathrm{2}}…
Question Number 219621 by ajfour last updated on 29/Apr/25 Commented by ajfour last updated on 29/Apr/25 $${Correction}:\:{A}\left(\mathrm{0},{k}^{\mathrm{2}} \right) \\ $$$${Find}\:{r}\:{in}\:{terms}\:{of}\:{k}. \\ $$ Answered by mr…
Question Number 219461 by alcohol last updated on 25/Apr/25 $${I}_{{n}} \:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{x}}{\left({x}\:+\:\mathrm{1}\right)^{{n}} }{dx} \\ $$$${find}\:{I}_{\mathrm{0}} \:{and}\:{I}_{\mathrm{1}} \\ $$$${express}\:{I}_{{n}} \:{interms}\:{of}\:{n}\:{for}\:{all}\:{n}\:\geqslant\:\mathrm{2} \\ $$ Answered by y0o0o…
Question Number 218357 by Spillover last updated on 08/Apr/25 Answered by Spillover last updated on 16/Apr/25 Answered by Spillover last updated on 17/Apr/25 Answered by…