Question Number 221184 by Lekhraj last updated on 26/May/25 Commented by mehdee7396 last updated on 26/May/25 $${A},{B}\:?\:{are}\:{thay}\:{focies} \\ $$ Commented by Lekhraj last updated on…
Question Number 221050 by MrGaster last updated on 23/May/25 Commented by MrGaster last updated on 23/May/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 220257 by abbb last updated on 10/May/25 $${proof}\:{that}\:{volume}\:{of}\:{frustum}\:{of} \\ $$$$\:{circular}\:{cone}\:{is}\:\frac{\mathrm{1}}{\mathrm{3}}{h}\left[{A}\mathrm{1}+{A}\mathrm{2}+\sqrt{{A}\mathrm{1}{A}\mathrm{2}}\right. \\ $$$${A}_{\mathrm{1}} {and}\:{A}_{\mathrm{2}} \:{are}\:\:{areas}\:{of}\:{base} \\ $$ Answered by MrGaster last updated on 10/May/25…
Question Number 219685 by alcohol last updated on 30/Apr/25 Answered by SdC355 last updated on 01/May/25 $$\kappa=\frac{\mathrm{2}}{\:\sqrt{\left(\mathrm{1}+\mathrm{4}{x}^{\mathrm{2}} \right)^{\mathrm{3}} }}\:\:\:\left(\mathrm{curvature}\:\kappa=\frac{\mid\mid{y}^{\left(\mathrm{2}\right)} \left({t}\right)\mid\mid}{\:\sqrt{\left(\mathrm{1}+\left({y}^{\left(\mathrm{1}\right)} \left({t}\right)\right)^{\mathrm{2}} \right)^{\mathrm{3}} }}\:\right) \\ $$$${r}=\frac{\mathrm{1}}{\kappa}=\frac{\sqrt{\left(\mathrm{1}+\mathrm{4}{x}^{\mathrm{2}}…
Question Number 219621 by ajfour last updated on 29/Apr/25 Commented by ajfour last updated on 29/Apr/25 $${Correction}:\:{A}\left(\mathrm{0},{k}^{\mathrm{2}} \right) \\ $$$${Find}\:{r}\:{in}\:{terms}\:{of}\:{k}. \\ $$ Answered by mr…
Question Number 219461 by alcohol last updated on 25/Apr/25 $${I}_{{n}} \:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{x}}{\left({x}\:+\:\mathrm{1}\right)^{{n}} }{dx} \\ $$$${find}\:{I}_{\mathrm{0}} \:{and}\:{I}_{\mathrm{1}} \\ $$$${express}\:{I}_{{n}} \:{interms}\:{of}\:{n}\:{for}\:{all}\:{n}\:\geqslant\:\mathrm{2} \\ $$ Answered by y0o0o…
Question Number 218357 by Spillover last updated on 08/Apr/25 Answered by Spillover last updated on 16/Apr/25 Answered by Spillover last updated on 17/Apr/25 Answered by…
Question Number 218356 by Spillover last updated on 08/Apr/25 Answered by Nicholas666 last updated on 09/Apr/25 $$\mathrm{8} \\ $$ Answered by Spillover last updated on…
Question Number 218384 by Spillover last updated on 08/Apr/25 Answered by Nicholas666 last updated on 09/Apr/25 $${percentage}\:{of}\:{red}\:{area}: \\ $$$$\frac{\mathrm{15}\pi\sqrt{\mathrm{3}}}{\mathrm{32}.\mathrm{3}}.\mathrm{100\%}=\frac{\mathrm{5}\pi\sqrt{\mathrm{3}}}{\mathrm{32}}=\mathrm{100\%} \\ $$$$=\frac{\mathrm{5}.\pi.\mathrm{1},\mathrm{732}}{\mathrm{32}}.\mathrm{100\%}=\frac{\mathrm{27},\mathrm{206}}{\mathrm{32}}.\mathrm{100\%}=\mathrm{85},\mathrm{02\%} \\ $$$$ \\ $$…
Question Number 218344 by Spillover last updated on 07/Apr/25 Commented by mr W last updated on 07/Apr/25 $$\mathrm{12}\leqslant{d}\leqslant\mathrm{10}+\mathrm{4}\sqrt{\mathrm{6}} \\ $$ Terms of Service Privacy Policy…