Question Number 187227 by ajfour last updated on 14/Feb/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 187142 by a.lgnaoui last updated on 14/Feb/23 $$\:{Montrer}\:{que}: \\ $$$$\mathrm{4}{r}^{\mathrm{2}} ={a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} +{d}^{\mathrm{2}} \\ $$$$ \\ $$ Commented by a.lgnaoui last updated…
Question Number 187059 by ajfour last updated on 13/Feb/23 Commented by ajfour last updated on 13/Feb/23 $${Bigger}\:{curve}\:\:\:{y}={x}^{\mathrm{3}} −{x}−{c} \\ $$$${the}\:{other}\:\:\:{y}={m}\left({x}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right)^{\mathrm{2}} \left({x}−{s}\right) \\ $$$${say}\:{their}\:{intersections}\:{be}\:{at} \\ $$$${x}={p},\:{q},\:{t}…
Question Number 121355 by john santu last updated on 07/Nov/20 Answered by liberty last updated on 07/Nov/20 $$\mathrm{using}\:\mathrm{the}\:\mathrm{formula}\:\Rightarrow\left(\mathrm{x}−\mathrm{x}_{\mathrm{1}} \right)\left(\mathrm{x}−\mathrm{x}_{\mathrm{2}} \right)+\left(\mathrm{y}−\mathrm{y}_{\mathrm{1}} \right)\left(\mathrm{y}−\mathrm{y}_{\mathrm{2}} \right)=\mathrm{0} \\ $$$$\mathrm{where}\:\mathrm{the}\:\mathrm{point}\:\left(\mathrm{x}_{\mathrm{1}} ,\mathrm{y}_{\mathrm{1}}…
Question Number 186835 by ajfour last updated on 11/Feb/23 Commented by ajfour last updated on 11/Feb/23 $${Curve}\:{is}\:{y}={x}^{\mathrm{3}} −{x} \\ $$$${Horizontal}\:{lines}\:{y}=\mathrm{0}\:{and}\:{y}={c} \\ $$$${Say}\:{a}\:{root}\:{of}\:{curve}\:{be}\:{x}={p}. \\ $$$${A}\left({p},\mathrm{0}\right)\:\:\: \\…
Question Number 186803 by ajfour last updated on 10/Feb/23 Answered by ajfour last updated on 10/Feb/23 $${Curve}\:{is}\:{y}={x}^{\mathrm{3}} −{x} \\ $$$${p}^{\mathrm{3}} −{p}={c} \\ $$$${m}=\mathrm{3}{s}^{\mathrm{2}} −\mathrm{1}=\frac{{p}−{h}}{{k}} \\…
Question Number 121244 by benjo_mathlover last updated on 06/Nov/20 Commented by liberty last updated on 06/Nov/20 Commented by liberty last updated on 06/Nov/20 $$\left(\mathrm{1}\right)\:\mathrm{sin}\:\mathrm{30}°=\frac{\mathrm{2}}{\mathrm{OA}}\:\Rightarrow\:\mathrm{OA}=\mathrm{4} \\…
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Question Number 55138 by Learner last updated on 18/Feb/19 Commented by math1967 last updated on 18/Feb/19 $${PT}^{\mathrm{2}} ={PA}×{PB} \\ $$$$\therefore{PA}=\frac{\mathrm{6}×\mathrm{6}}{\mathrm{3}}=\mathrm{12}{cm} \\ $$$$\therefore{AB}=\mathrm{12}−\mathrm{3}=\mathrm{9}{cm} \\ $$ Terms…
Question Number 55072 by peter frank last updated on 17/Feb/19 Commented by mr W last updated on 17/Feb/19 $$\left({ax}+{by}\right)\left({bx}−{ay}\right)=\mathrm{0} \\ $$$${abx}^{\mathrm{2}} −\left({a}^{\mathrm{2}} −{b}^{\mathrm{2}} \right){xy}−{aby}^{\mathrm{2}} =\mathrm{0}…