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Question Number 52058 by peter frank last updated on 02/Jan/19 Answered by tanmay.chaudhury50@gmail.com last updated on 02/Jan/19 $${eqn}\:{ellipse}\:\frac{{x}^{\mathrm{2}} }{{a}^{\mathrm{2}} }+\frac{{y}^{\mathrm{2}} }{{b}^{\mathrm{2}} }=\mathrm{1}\:\: \\ $$$${focus}\left({ae},\mathrm{0}\right) \\…
Question Number 51921 by peter frank last updated on 01/Jan/19 $${A}\:{normal}\:{chord}\:{to}\:{an}\: \\ $$$${ellipse}\:\frac{{x}^{\mathrm{2}} }{{a}^{\mathrm{2}} }+\frac{{y}^{\mathrm{2}} }{{b}^{\mathrm{2}} }=\mathrm{1} \\ $$$${make}\:{an}\:{angle}\:{of}\:\mathrm{45}^{°} \\ $$$${with}\:{the}\:{axis}.{prove} \\ $$$${that}\:{the}\:{square}\:{of}\:{its}\: \\ $$$${length}\:{is}\:{equal}\:{to}…
Question Number 51901 by peter frank last updated on 31/Dec/18 $${Prove}\:{that}\:{the}\:{two}\: \\ $$$${parabola}\:{y}^{\mathrm{2}} =\mathrm{4}{ax}\:{and} \\ $$$${y}^{\mathrm{2}} =\mathrm{4}{c}\left({x}−{b}\right)\:{cannot} \\ $$$${have}\:{a}\:{common}\:{normal} \\ $$$${other}\:{than}\:{the}\:{axis}\:{unless} \\ $$$$\frac{{b}}{{a}−{c}}>\mathrm{2} \\ $$…
Question Number 51869 by prakash jain last updated on 31/Dec/18 Commented by prakash jain last updated on 31/Dec/18 $$\mathrm{Correct}\:\mathrm{answer}\:\mathrm{given}\:\mathrm{is}\:\mathrm{2}/\mathrm{9}. \\ $$$$\mathrm{I}\:\mathrm{think}\:\mathrm{mininum}\:\mathrm{is}\:\mathrm{0}. \\ $$ Answered by…
Question Number 51822 by peter frank last updated on 30/Dec/18 $${If}\:\:{p}\:{and}\:{q}\:\:{are}\:{the}\:{length} \\ $$$${of}\:{perpendicular}\:{from} \\ $$$${the}\:{origin}\:{to}\:{the}\:{lines} \\ $$$${x}\mathrm{cos}\:\theta−{y}\mathrm{sin}\:\:\theta={kcos}\mathrm{2}\theta \\ $$$${and}\:{x}\mathrm{sec}\:\theta+{y}\mathrm{cosec}\:\theta={k} \\ $$$${respectively} \\ $$$${prove}\:{that} \\ $$$${p}^{\mathrm{2}}…
Question Number 51818 by peter frank last updated on 30/Dec/18 $${Find}\:{the}\:{relation}\:{between} \\ $$$${the}\:{ecentric}\:{angles} \\ $$$${of}\:{the}\:{point}\:\:{which}\:{are} \\ $$$${at}\:{the}\:{end}\:{of}\:{focal}\:{chord} \\ $$ Terms of Service Privacy Policy Contact:…