Question Number 212647 by golsendro last updated on 20/Oct/24 $$\:\:\:\sqrt{\mathrm{x}−\frac{\mathrm{1}}{\mathrm{x}}}\:+\sqrt{\mathrm{1}−\frac{\mathrm{1}}{\mathrm{x}}}\:=\:\mathrm{x}\: \\ $$ Commented by Rasheed.Sindhi last updated on 21/Oct/24 $${See}\:{also}\:{Q}#\mathrm{200498} \\ $$ Answered by Frix…
Question Number 212630 by efronzo1 last updated on 19/Oct/24 Commented by efronzo1 last updated on 19/Oct/24 $$\:\: \\ $$ Answered by mr W last updated…
Question Number 212377 by yadavd last updated on 12/Oct/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 211953 by efronzo1 last updated on 25/Sep/24 Commented by BHOOPENDRA last updated on 25/Sep/24 $${h}=\frac{\sqrt{\mathrm{2}}\:\left(\sqrt{{ab}}\:−{a}\:+{b}−{c}\right)}{\:\sqrt{\left(\sqrt{{ab}}\right)+{b}}} \\ $$ Commented by BHOOPENDRA last updated on…
Question Number 211495 by BaliramKumar last updated on 11/Sep/24 Answered by Rasheed.Sindhi last updated on 11/Sep/24 $${Let}\:{n}=\mathrm{10}{m} \\ $$$${HCF}\left(\mathrm{10}{m},\mathrm{10}\left({m}+\mathrm{1}\right)\right)=\mathrm{10} \\ $$$${HCF}\left({m},{m}+\mathrm{1}\right)=\mathrm{1}\Rightarrow{m}=\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},… \\ $$$$\therefore{LCM}={x}\left(\mathrm{2}-{digit}\:{numbers}\right)=\mathrm{10}{m}\left({m}+\mathrm{1}\right)\: \\ $$$$\:\:\:\:\:\:=\mathrm{20},\mathrm{60}\:\left(\mathrm{2}\:{possible}\:{values}\right)…
Question Number 211430 by a.lgnaoui last updated on 09/Sep/24 $$\mathrm{determiner}\:\mathrm{les}\:\mathrm{valeurs}\:\mathrm{demandees} \\ $$$$\mathrm{en}\:\mathrm{finction}\:\mathrm{des}\:\mathrm{donnes}\::\boldsymbol{\mathrm{a}},\:\boldsymbol{\mathrm{b}}\:,\mathrm{angle}\:\:\boldsymbol{\mathrm{F}}\mathrm{2} \\ $$$$\left(\mathrm{h}=\boldsymbol{\mathrm{MH}}\right) \\ $$ Commented by a.lgnaoui last updated on 09/Sep/24 Terms of…
Question Number 211294 by Jubr last updated on 05/Sep/24 Commented by a.lgnaoui last updated on 05/Sep/24 Commented by Ghisom last updated on 05/Sep/24 $$\mathrm{just}\:\mathrm{saying}:\:\mathrm{it}'\mathrm{s}\:\mathrm{not}\:\mathrm{convex} \\…
Question Number 211216 by Jubr last updated on 31/Aug/24 Answered by nikif99 last updated on 31/Aug/24 Commented by Jubr last updated on 31/Aug/24 $${Thank}\:{you}\:{sir} \\…
Question Number 211180 by Durganand last updated on 30/Aug/24 Answered by mr W last updated on 30/Aug/24 $$\left({ax}+{by}+{c}\right)\left(\frac{{x}}{{a}}+\frac{{y}}{{b}}+{d}\right) \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\left(\frac{{a}}{{b}}+\frac{{b}}{{a}}\right){xy}+\left({ad}+\frac{{c}}{{a}}\right){x}+\left({bd}+\frac{{c}}{{b}}\right)+{cd} \\ $$$$={x}^{\mathrm{2}} +{y}^{\mathrm{2}}…
Question Number 211141 by Durganand last updated on 29/Aug/24 Terms of Service Privacy Policy Contact: info@tinkutara.com