Question Number 175406 by princeDera last updated on 29/Aug/22 $$\frac{{d}^{\mathrm{2}} \boldsymbol{{y}}}{\boldsymbol{{dx}}^{\mathrm{2}} }\:−\mathrm{tan}\:\left(\boldsymbol{{x}}\right)\frac{\boldsymbol{{dy}}}{\boldsymbol{{dx}}}\:=\:\mathrm{0} \\ $$ Answered by Ar Brandon last updated on 29/Aug/22 $${y}''−\mathrm{tan}{x}\centerdot{y}'=\mathrm{0} \\ $$$$\Rightarrow\frac{{y}''}{{y}'}=\mathrm{tan}{x}…
Question Number 175041 by rexford last updated on 17/Aug/22 $${Solve}\:{the}\:{differential} \\ $$$$\frac{{dy}}{{dx}}=\frac{{x}^{\mathrm{2}} −\mathrm{3}{xy}}{{x}+{y}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 43616 by Tawa1 last updated on 12/Sep/18 $$\mathrm{Solve}:\:\:\:\mathrm{x}^{\mathrm{2}} \mathrm{y}''\:\:+\:\:\mathrm{xy}'\:\:−\:\mathrm{y}\:=\:\mathrm{x}\:,\:\:\:\:\:\:\:\:\mathrm{y}_{\mathrm{1}} \:=\:\mathrm{x} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 13/Sep/18 $${x}={e}^{{t}} \:\:\:\frac{{dx}}{{dt}}={e}^{{t}} \\ $$$$\frac{{dy}}{{dx}}=\frac{{dy}}{{dt}}×\frac{{dt}}{{dx}}=\frac{{dy}}{{dt}}×\frac{\mathrm{1}}{{e}^{{t}}…
Question Number 43599 by rish@bh last updated on 12/Sep/18 $$\frac{{dy}}{{dx}}\left({x}^{\mathrm{2}} {y}^{\mathrm{2}} +{xy}\right)=\mathrm{1} \\ $$$$\mathrm{Solve}\:\mathrm{differential}\:\mathrm{equation} \\ $$$$\mathrm{Thanks} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 108836 by bemath last updated on 19/Aug/20 $$\:\:\frac{\boldsymbol{{bemath}}}{\subset{cooll}\supset} \\ $$$${find}\:{the}\:{particular}\:{solution}\: \\ $$$${of}\:{y}''\:+\:\mathrm{4}{y}\:=\:\mathrm{sin}\:\left(\mathrm{2}{x}\right) \\ $$ Answered by john santu last updated on 19/Aug/20 Terms…
Question Number 108491 by Ar Brandon last updated on 17/Aug/20 $$\left(\mathrm{1}+\mathrm{2x}\right)\mathrm{y}''+\left(\mathrm{4x}−\mathrm{2}\right)\mathrm{y}'−\mathrm{8y}=\mathrm{0} \\ $$ Answered by Ar Brandon last updated on 20/Aug/20 $$\mathrm{6}.\:\left(\mathrm{1}+\mathrm{2x}\right)\mathrm{y}''+\left(\mathrm{4x}−\mathrm{2}\right)\mathrm{y}'−\mathrm{8y}=\mathrm{0} \\ $$$$\Rightarrow\left(\mathrm{2x}+\mathrm{1}\right)\left(\mathrm{y}''+\mathrm{2y}'\right)+\mathrm{4}\left(\mathrm{y}'+\mathrm{2y}\right)=\mathrm{0} \\…
Question Number 108473 by subhankar10 last updated on 17/Aug/20 $$\mathrm{3x}^{\mathrm{3}} +\mathrm{4x}−\mathrm{3}=\mathrm{0} \\ $$$$\mathrm{solve}\:\mathrm{this}\:\mathrm{problem}. \\ $$ Answered by Sarah85 last updated on 17/Aug/20 $${x}^{\mathrm{3}} +\frac{\mathrm{4}}{\mathrm{3}}{x}−\mathrm{1}=\mathrm{0} \\…
Question Number 108475 by pticantor last updated on 17/Aug/20 $$\left({x}^{\mathrm{2}} +\mathrm{1}\right)\boldsymbol{{y}}^{'} +\mathrm{2}{x}\boldsymbol{{y}}={x}\sqrt{{x}^{\mathrm{2}} +\mathrm{1}} \\ $$$${please}\:{solve}\:{this}\:{differential} \\ $$$${equation} \\ $$ Answered by Dwaipayan Shikari last updated…
Question Number 108353 by bemath last updated on 16/Aug/20 $$\:\:\:\:\:\:\frac{\bigtriangleup\mathcal{B}{e}\mathcal{M}{ath}\bigtriangleup}{\ldots} \\ $$$$\:{General}\:{solution}\:{of}\: \\ $$$$\:\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\:+\:\frac{{dy}}{{dx}}−\mathrm{2}{y}\:=\:\mathrm{sin}\:{x}\: \\ $$ Commented by bemath last updated on 16/Aug/20…
Question Number 108227 by Ar Brandon last updated on 15/Aug/20 $$\mathrm{y}''+\mathrm{4y}'+\mathrm{5y}=\mathrm{xe}^{−\mathrm{2x}} \mathrm{sinx} \\ $$ Answered by mathmax by abdo last updated on 15/Aug/20 $$\mathrm{h}\rightarrow\mathrm{r}^{\mathrm{2}} +\mathrm{4r}+\mathrm{5}=\mathrm{0}\rightarrow\Delta^{'}…