Question Number 28954 by Ruchinna1 last updated on 02/Feb/18 $${please}\:{solve}\:\mathrm{4},\mathrm{5},\mathrm{6} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 94328 by i jagooll last updated on 18/May/20 $$\mathrm{y}'\:+\:\mathrm{xy}\:=\:\mathrm{x}\: \\ $$ Answered by i jagooll last updated on 18/May/20 Commented by i jagooll…
Question Number 94239 by i jagooll last updated on 17/May/20 $$\mathrm{x}^{\mathrm{2}} \:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{x}^{\mathrm{2}} +\mathrm{xy}+\mathrm{y}^{\mathrm{2}} \\ $$ Answered by i jagooll last updated on 17/May/20 Commented by…
Question Number 28468 by tawa tawa last updated on 26/Jan/18 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{for}\:\mathrm{all}\:\mathrm{values}\:\mathrm{of}\:\mathrm{u},\:\mathrm{the}\:\mathrm{point}\:\left[\mathrm{a}\:\mathrm{cosh}\left(\mathrm{u}\right)\:,\:\:\mathrm{b}\:\mathrm{sinh}\left(\mathrm{u}\right)\right]\:\mathrm{lies}\:\mathrm{on}\:\mathrm{the}\: \\ $$$$\mathrm{hyperbola}\:\mathrm{whose}\:\mathrm{equation}\:\mathrm{is}.\:\:\:\:\:\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{a}^{\mathrm{2}} }\:−\:\frac{\mathrm{y}^{\mathrm{2}} }{\mathrm{b}^{\mathrm{2}} }\:=\:\mathrm{1} \\ $$$$\mathrm{And}\:\mathrm{that}\:\mathrm{the}\:\mathrm{tangent}\:\mathrm{at}\:\mathrm{that}\:\mathrm{point}\:\mathrm{is}\::\:\:\:\frac{\mathrm{x}}{\mathrm{a}}\:\mathrm{cosh}\left(\mathrm{u}\right)\:\:−\:\:\frac{\mathrm{y}}{\mathrm{b}}\:\mathrm{sinh}\left(\mathrm{u}\right) \\ $$ Terms of Service Privacy…
Question Number 93900 by i jagooll last updated on 16/May/20 $$\mathrm{y}''+\mathrm{2}{xy}=\:\mathrm{y} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 93828 by i jagooll last updated on 15/May/20 $$\mathrm{sin}\:\mathrm{x}\:\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)−\mathrm{y}\:=\:\mathrm{2sin}\:\mathrm{x}\: \\ $$ Commented by i jagooll last updated on 15/May/20 Commented by mathmax by…
Question Number 93818 by i jagooll last updated on 15/May/20 $$\left(\mathrm{y}−\mathrm{xy}^{\mathrm{2}} \right)\mathrm{dx}\:+\left(\mathrm{x}+\mathrm{x}^{\mathrm{2}} \mathrm{y}^{\mathrm{2}} \right)\mathrm{dy}\:=\:\mathrm{0} \\ $$ Answered by i jagooll last updated on 15/May/20 $$\mathrm{ydx}+\mathrm{xdy}=\mathrm{xy}^{\mathrm{2}}…
Question Number 28280 by Cheyboy last updated on 23/Jan/18 $${Find}\:{dy}/{dx} \\ $$$${x}^{\frac{\mathrm{2}}{\mathrm{3}}} \left(\mathrm{6}−{x}\right)^{\frac{\mathrm{1}}{\mathrm{3}\:}} \:{to}\:{it}\:{simplest}\:{form} \\ $$ Commented by abdo imad last updated on 23/Jan/18 $${we}\:{have}\:{y}\left({x}\right)=\left({x}^{\mathrm{2}}…
Question Number 93815 by i jagooll last updated on 15/May/20 $$\left(\mathrm{D}^{\mathrm{2}} +\mathrm{6D}+\mathrm{9}\right)\mathrm{y}\:=\:\frac{\mathrm{e}^{−\mathrm{3x}} }{\mathrm{x}^{\mathrm{3}} }\: \\ $$ Answered by john santu last updated on 15/May/20 $$\mathrm{homogenous}\:\mathrm{solution}…
Question Number 159346 by Ar Brandon last updated on 15/Nov/21 $${xy}''+\mathrm{2}\left({x}+\mathrm{1}\right){y}'+\left({x}+\mathrm{2}\right){y}=\mathrm{0} \\ $$ Answered by mindispower last updated on 16/Nov/21 $${x}\left({y}''+\mathrm{2}{y}'+{y}\right)+\left({y}'+{y}\right) \\ $$$$={x}\left(\left({y}'+{y}\right)'+\left({y}'+{y}\right)\right)+\left({y}'+{y}\right)=\mathrm{0} \\ $$$${z}={y}+{y}'…