Question Number 93786 by mr W last updated on 14/May/20 $${find}\:{f}\left({x}\right)\:{such}\:{that} \\ $$$${f}\:'\left({x}\right)={f}^{−\mathrm{1}} \left({x}\right) \\ $$ Answered by john santu last updated on 15/May/20 $$\mathrm{f}\left(\mathrm{x}\right)=\:\sqrt[{\varphi}]{\frac{\mathrm{1}}{\varphi}}\:\mathrm{x}^{\varphi}…
Question Number 159319 by nimnim last updated on 15/Nov/21 $$\:\:\:\:\:\:\:\frac{\mathrm{dy}}{\mathrm{dx}}+\frac{\mathrm{x}−\mathrm{y}−\mathrm{2}}{\mathrm{x}−\mathrm{2y}−\mathrm{3}}=\mathrm{0} \\ $$$$\mathrm{Pls}…\:\mathrm{solve}\:\mathrm{the}\:\mathrm{differential}\:\mathrm{equation}. \\ $$ Answered by mr W last updated on 15/Nov/21 $${let} \\ $$$${x}={u}+{a}…
Question Number 93707 by i jagooll last updated on 14/May/20 $$\mathrm{y}\:\mathrm{y}''\:=\:\left(\mathrm{y}'\right)^{\mathrm{2}} \: \\ $$ Commented by i jagooll last updated on 14/May/20 cool man Commented by…
Question Number 93620 by i jagooll last updated on 14/May/20 $$\left(\mathrm{3x}+\mathrm{3y}−\mathrm{4}\right)\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{x}+\mathrm{y}\: \\ $$ Answered by john santu last updated on 14/May/20 $${r}\:=\:{x}+{y}\:\Rightarrow\:\frac{{dr}}{{dx}}\:=\:\mathrm{1}+\:\frac{{dy}}{{dx}} \\ $$$$\left(\mathrm{3}{r}−\mathrm{4}\right)\left(\frac{{dr}}{{dx}}−\mathrm{1}\right)\:=\:{r}\: \\…
Question Number 93312 by john santu last updated on 12/May/20 $$\left(\mathrm{y}−\mathrm{xy}^{\mathrm{2}} \right)\mathrm{dx}+\left(\mathrm{x}+\mathrm{x}^{\mathrm{2}} \mathrm{y}^{\mathrm{2}} \right)\mathrm{dy}\:=\:\mathrm{0}\: \\ $$ Answered by i jagooll last updated on 12/May/20 $$\mathrm{ydx}+\mathrm{xdy}\:−\left(\mathrm{xy}^{\mathrm{2}}…
Question Number 93283 by john santu last updated on 12/May/20 $$\frac{{dy}}{{dx}}\:=\:\mathrm{2}{x}^{\mathrm{2}} +{y}^{\mathrm{2}} \:,\:\mathrm{y}\left(\mathrm{0}\right)\:=\:\mathrm{1}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 27696 by chernoaguero@gmail.com last updated on 12/Jan/18 $$ \\ $$$$ \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{ae}^{\mathrm{x}} +\mathrm{3e}^{\mathrm{2x}} −\mathrm{b}}{\mathrm{x}}\:=\mathrm{8} \\ $$$$ \\ $$$$\mathrm{find}\:\mathrm{a}\:\mathrm{and}\:\mathrm{b} \\ $$ Commented by…
Question Number 93059 by Ar Brandon last updated on 10/May/20 $$\mathrm{y}^{'} +\mathrm{2xy}=\mathrm{cos}\:\mathrm{x}+\mathrm{2x}\:\mathrm{sin}\:\mathrm{x} \\ $$ Answered by TANMAY PANACEA … last updated on 10/May/20 $${dy}+\mathrm{2}{xydx}={cosxdx}+\mathrm{2}{xsinxdx} \\…
Question Number 93003 by i jagooll last updated on 10/May/20 $$\left(\mathrm{x}^{\mathrm{2}} −\mathrm{2xy}−\mathrm{y}^{\mathrm{2}} \right)\mathrm{dx}−\left(\mathrm{x}−\mathrm{y}\right)^{\mathrm{2}} \:\mathrm{dy}=\mathrm{0} \\ $$ Answered by TANMAY PANACEA … last updated on 10/May/20…
Question Number 92860 by i jagooll last updated on 09/May/20 $$\sqrt{\mathrm{1}−\mathrm{x}^{\mathrm{2}} }\:\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{x}\right)\:\mathrm{dy}\:+\:\mathrm{y}\:\mathrm{dx}\:=\:\mathrm{0}\: \\ $$ Commented by john santu last updated on 09/May/20 $$\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }\:\mathrm{sin}^{−\mathrm{1}}…