Question Number 86003 by jagoll last updated on 26/Mar/20 $$\mathrm{y}\:''\:+\:\mathrm{y}'\:=\:\mathrm{sin}\:\mathrm{x}\:\mathrm{cos}\:\mathrm{2x} \\ $$ Commented by mathmax by abdo last updated on 26/Mar/20 $${let}\:{y}^{'} ={z}\:\:\:\left({e}\right)\Rightarrow{z}^{'} \:+{z}\:={sinx}\:{cos}\mathrm{2}{x} \\…
Question Number 85835 by sahnaz last updated on 25/Mar/20 $$\mathrm{xydy}=\left(\mathrm{y}^{\mathrm{2}} +\mathrm{x}\right)\mathrm{dx} \\ $$ Answered by TANMAY PANACEA. last updated on 25/Mar/20 $${xydy}−{y}^{\mathrm{2}} {dx}={xdx} \\ $$$${y}\left({xdy}−{ydx}\right)={xdx}…
Question Number 85834 by sahnaz last updated on 25/Mar/20 $$\mathrm{2y}^{'} −\frac{\mathrm{x}}{\mathrm{y}}=\frac{\mathrm{xy}}{\mathrm{x}^{\mathrm{2}} −\mathrm{1}} \\ $$ Answered by mind is power last updated on 27/Mar/20 $$\Leftrightarrow\mathrm{2}{y}'{y}−{x}=\frac{{xy}^{\mathrm{2}} }{{x}^{\mathrm{2}}…
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Question Number 85766 by jagoll last updated on 24/Mar/20 $$\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{1}−\mathrm{sin}\:\left(\mathrm{x}+\mathrm{2y}\right) \\ $$ Commented by jagoll last updated on 24/Mar/20 $$\mathrm{u}\:=\:\mathrm{x}+\mathrm{2y} \\ $$$$\frac{\mathrm{du}}{\mathrm{dx}}\:=\:\mathrm{1}+\mathrm{2}\frac{\mathrm{dy}}{\mathrm{dx}} \\ $$$$\frac{\mathrm{2dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{du}}{\mathrm{dx}}−\mathrm{1}\:\Rightarrow\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\left[\:\frac{\mathrm{du}}{\mathrm{dx}}−\mathrm{1}\right] \\…
Question Number 85503 by john santu last updated on 22/Mar/20 $$\frac{{dy}}{{dx}}\:=\:\mathrm{sec}\:\left({x}+{y}\right)\: \\ $$ Answered by mr W last updated on 22/Mar/20 $${u}={x}+{y} \\ $$$$\frac{{du}}{{dx}}=\mathrm{1}+\frac{{dy}}{{dx}} \\…
Question Number 85356 by jagoll last updated on 21/Mar/20 $$\left(\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} \right)\:=\:\mathrm{3xy}^{\mathrm{2}} \:\frac{\mathrm{dy}}{\mathrm{dx}} \\ $$ Answered by jagoll last updated on 21/Mar/20 Terms of Service…
Question Number 85250 by niroj last updated on 20/Mar/20 $$\:\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{general}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{singular}}\:\boldsymbol{\mathrm{solution}}\:\boldsymbol{\mathrm{of}}\: \\ $$$$\:\left(\mathrm{i}\right).\:\boldsymbol{\mathrm{y}}=\:\boldsymbol{\mathrm{px}}\:+\:\boldsymbol{\mathrm{p}}^{\boldsymbol{\mathrm{n}}} \\ $$$$\left(\mathrm{ii}\right).\:\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{a}}\right)\boldsymbol{\mathrm{p}}^{\mathrm{2}} +\left(\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{y}}\right)\boldsymbol{\mathrm{p}}−\boldsymbol{\mathrm{y}}=\mathrm{0} \\ $$$$\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 85116 by niroj last updated on 19/Mar/20 $$\:\mathrm{Reduce}\:\mathrm{the}\:\mathrm{equations}\:\mathrm{to}\:\mathrm{Clairaut}'\mathrm{s}\:\mathrm{form} \\ $$$$\:\mathrm{and}\:\mathrm{find}\:\mathrm{the}\:\mathrm{general}\:\mathrm{solution}\:: \\ $$$$\:\boldsymbol{\mathrm{x}}^{\mathrm{2}} \boldsymbol{\mathrm{p}}^{\mathrm{2}} +\boldsymbol{\mathrm{yp}}\left(\mathrm{2}\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{y}}\right)+\boldsymbol{\mathrm{y}}^{\mathrm{2}} =\mathrm{0}\:\:\:\:\:\:\left({put}\:\boldsymbol{{y}}=\boldsymbol{{u}}\:{and}\:\boldsymbol{{xy}}=\boldsymbol{{v}}\right) \\ $$$$\: \\ $$ Commented by MJS last…
Question Number 85050 by john santu last updated on 18/Mar/20 $$\left(\mathrm{x}−\mathrm{4y}+\mathrm{3}\right)\mathrm{dx}\:=\:\left(\mathrm{x}−\mathrm{5y}+\mathrm{4}\right)\mathrm{dy} \\ $$ Answered by mr W last updated on 18/Mar/20 $${let} \\ $$$${x}={u}+{a} \\…