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Question Number 142200 by liberty last updated on 27/May/21 $$\:{Let}\:{p}\:\&\:{q}\:{real}\:{positive}\:{number} \\ $$$$\:\:{what}\:{the}\:{minimum}\:{of}\:\left(\frac{{p}^{\mathrm{2}} }{{q}^{\mathrm{2}} }\:+\frac{{q}}{{p}}\right)^{\mathrm{3}} . \\ $$ Answered by MJS_new last updated on 27/May/21 $$\mathrm{let}\:{q}={pt}\wedge{t}>\mathrm{0}…
Question Number 10956 by Joel576 last updated on 04/Mar/17 $${y}\:=\:\frac{{x}\:−\:\mathrm{2}}{\mathrm{2}\left({x}\:−\:\mathrm{1}\right)^{\mathrm{3}/\mathrm{2}} } \\ $$$$\mathrm{Let}\:\:{p}\:=\:{x}\:−\:\mathrm{1} \\ $$$$\Rightarrow\:{y}\:=\:\frac{{p}\:−\:\mathrm{1}}{\mathrm{2}{p}^{\mathrm{3}/\mathrm{2}} } \\ $$$$ \\ $$$$\mathrm{Is}\:\mathrm{it}\:\mathrm{true}\:\mathrm{that}\:\:\:\frac{{dy}}{{dx}}\:\:\:=\:\:\frac{{dy}}{{dp}}\:\:? \\ $$ Commented by FilupS…
Question Number 141947 by mnjuly1970 last updated on 25/May/21 $$ \\ $$$$\:\:\:\:\:\:\Omega:=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\sqrt{\mathrm{1}−{x}}\:{arcsin}\left({x}\right)}{\:\sqrt{\mathrm{1}+{x}}}{dx}=?? \\ $$ Answered by qaz last updated on 25/May/21 $$\Omega=\int_{\mathrm{0}} ^{\mathrm{1}}…
Question Number 141916 by mnjuly1970 last updated on 24/May/21 $$ \\ $$$$\:\:\:\:\:{prove}\:\:{that}:: \\ $$$$\:\:\:\mathrm{I}:=\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} {arccosh}\left({sin}\left({x}\right)+{cos}\left({x}\right)\right){dx}=\frac{\pi}{\mathrm{2}}{ln}\left(\mathrm{2}\right)\:.. \\ $$ Answered by mindispower last updated on 25/May/21…
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Question Number 76250 by Mikael_786 last updated on 25/Dec/19 Commented by Mikael_786 last updated on 25/Dec/19 $${how}\:{to}\:{find}\:{tranform}\:{laplace}\:{invers}? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 10711 by Saham last updated on 23/Feb/17 $$\mathrm{If}\:\mathrm{y}\:=\:\mathrm{x}^{\mathrm{x}^{\mathrm{x}} } \:,\:\:\mathrm{find}\:\frac{\mathrm{dy}}{\mathrm{dx}} \\ $$ Answered by mrW1 last updated on 23/Feb/17 $${u}={x}^{{x}} \\ $$$$\mathrm{ln}\:{u}={x}\mathrm{ln}\:{x} \\…
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Question Number 141716 by qaz last updated on 22/May/21 $$\left({x}^{\mathrm{2}} {lnx}\right){y}''−{xy}'+{y}=\mathrm{0} \\ $$ Answered by mnjuly1970 last updated on 23/May/21 $$\:\:{y}_{{p}_{\mathrm{1}} } ={ln}\left({x}\right)+\mathrm{1}\:\:\:\:\:\:\:\:{or}\:\:\:\:{y}_{{p}_{\mathrm{1}} } ={x}…