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Question Number 9306 by tawakalitu last updated on 29/Nov/16 $$\mathrm{Differentiate}\:\mathrm{from}\:\mathrm{the}\:\mathrm{first}\:\mathrm{principle}: \\ $$$$\mathrm{y}\:=\:\mathrm{tan2x} \\ $$ Answered by mrW last updated on 30/Nov/16 $$\mathrm{y}\left(\mathrm{x}\right)=\mathrm{tan}\:\left(\mathrm{2x}\right) \\ $$$$\mathrm{y}\left(\mathrm{x}+\mathrm{h}\right)=\mathrm{tan}\:\left(\mathrm{2x}+\mathrm{2h}\right)=\frac{\mathrm{tan}\:\left(\mathrm{2x}\right)+\mathrm{tan}\:\left(\mathrm{2h}\right)}{\mathrm{1}−\mathrm{tan}\:\left(\mathrm{2x}\right)×\mathrm{tan}\:\left(\mathrm{2h}\right)} \\…
Question Number 140369 by meetbhavsar25 last updated on 06/May/21 Commented by meetbhavsar25 last updated on 08/May/21 $${mr}\:{W},\:{please}\:{help}\:{me}\:{out} \\ $$ Answered by john_santu last updated on…
Question Number 140363 by cesarL last updated on 06/May/21 $${My}\:{friends}\:{can}\:{you}\:{help}\:{me}? \\ $$$${f}\left({x},{y}\right)={x}^{\mathrm{3}} {y}^{\mathrm{7}} −\mathrm{4}{e}^{{x}−{y}} \\ $$$${Find}: \\ $$$$\left.{a}\right)\:\frac{\partial^{\mathrm{2}} {f}}{\partial{x}\partial{y}}=? \\ $$$$\left.{b}\right)\:\frac{\partial^{\mathrm{2}} {f}^{\mathrm{2}} }{\partial{y}\partial{x}}=? \\ $$$${Please}…
Question Number 9268 by Adarsh last updated on 27/Nov/16 $$\mathrm{2}+\mathrm{x}=\mathrm{3} \\ $$ Answered by FilupSmith last updated on 27/Nov/16 $${x}=\mathrm{1} \\ $$ Terms of Service…
Question Number 9231 by tawakalitu last updated on 24/Nov/16 $$\mathrm{Differentiate}\::\:\:\mathrm{sin}\sqrt{\mathrm{x}}\:\:\:\:\mathrm{from}\:\mathrm{the} \\ $$$$\mathrm{first}\:\mathrm{principle}. \\ $$ Answered by mrW last updated on 29/Nov/16 $$\mathrm{y}\left(\mathrm{x}\right)=\mathrm{sin}\:\sqrt{\mathrm{x}} \\ $$$$\mathrm{y}\left(\mathrm{x}+\mathrm{h}\right)=\mathrm{sin}\:\sqrt{\mathrm{x}+\mathrm{h}} \\…
Question Number 140294 by solihin last updated on 06/May/21 Answered by Satyendra last updated on 06/May/21 $$\left.{c}\right)\:\mathrm{sin}^{−\mathrm{1}} {y}^{\mathrm{2}} =\mathrm{sin}{h}\left({xy}\right) \\ $$$$\Rightarrow\frac{\mathrm{2}{y}}{\:\sqrt{\mathrm{1}−{y}^{\mathrm{4}} }}\:{y}'=\mathrm{cos}{h}\left({xy}\right) \left({y}+{xy}'\right) \\ $$$$\Rightarrow\frac{\mathrm{2}{y}}{\:\sqrt{\mathrm{1}−{y}^{\mathrm{4}}…
Question Number 140288 by liberty last updated on 06/May/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{point}\left(\mathrm{s}\right)\:\mathrm{on}\:\mathrm{the}\:\mathrm{graph} \\ $$$$\mathrm{of}\:\mathrm{3x}^{\mathrm{2}} +\mathrm{10xy}+\mathrm{3y}^{\mathrm{2}} =\mathrm{9}\:\mathrm{closest}\:\mathrm{to} \\ $$$$\mathrm{the}\:\mathrm{origin} \\ $$ Answered by mr W last updated on…
Question Number 140270 by liberty last updated on 06/May/21 $$\mathrm{If}\:\left(\mathrm{x}−\mathrm{3}\right)^{\mathrm{2}} +\left(\mathrm{y}−\mathrm{4}\right)^{\mathrm{2}} \:=\:\mathrm{25}\:, \\ $$$$\mathrm{what}\:\mathrm{maximum}\:\mathrm{and}\:\mathrm{minimum} \\ $$$$\mathrm{value}\:\mathrm{of}\:\mathrm{7x}+\mathrm{8y}\:? \\ $$ Answered by EDWIN88 last updated on 06/May/21…
Question Number 74723 by necxxx last updated on 29/Nov/19 $$\mathrm{3}{xy}+{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{5} \\ $$$${find}\:{the}\:{second}\:{derivative} \\ $$ Commented by mathmax by abdo last updated on 29/Nov/19…