Question Number 226910 by Estevao last updated on 18/Dec/25 Answered by Estevao last updated on 18/Dec/25 $$>{Ashed}\:{Area} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 226908 by mr W last updated on 18/Dec/25 Commented by mr W last updated on 18/Dec/25 $${find}\:{the}\:{area}\:{of}\:{the}\:{circle}. \\ $$ Terms of Service Privacy…
Question Number 226850 by cherokeesay last updated on 17/Dec/25 Answered by TonyCWX last updated on 17/Dec/25 $${y}\:=\:{x}\left({x}−\mathrm{1}\right)\:\Rightarrow\:{x}\:=\:\mathrm{0}\:\mathrm{or}\:{x}\:=\:\mathrm{1} \\ $$$$\mathrm{A}>\mathrm{0},\:\mathrm{A}=\mathrm{1} \\ $$$$ \\ $$$${x}\left({x}−\mathrm{1}\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}}{x} \\ $$$${x}^{\mathrm{2}}…
Question Number 226796 by sonukgindia last updated on 15/Dec/25 Answered by mr W last updated on 15/Dec/25 Commented by mr W last updated on 15/Dec/25…
Question Number 226705 by mr W last updated on 10/Dec/25 Answered by fantastic2 last updated on 11/Dec/25 Commented by fantastic2 last updated on 11/Dec/25 $$\bigtriangleup{OPQ}\cong\bigtriangleup{SRQ}…
Question Number 226524 by wongb1506 last updated on 02/Dec/25 Answered by som(math1967) last updated on 02/Dec/25 $$\:\alpha=\mathrm{3}{x}\:\:\beta=\mathrm{2}{x} \\ $$$$\mathrm{5}{x}=\mathrm{90}\Rightarrow{x}=\mathrm{18}=\alpha−\beta \\ $$$$\:\:\left({D}\right) \\ $$ Terms of…
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Question Number 226525 by wongb1506 last updated on 02/Dec/25 Answered by som(math1967) last updated on 02/Dec/25 $${AF}=\sqrt{\mathrm{160}}\:,{AE}=\sqrt{\mathrm{180}}\:,\:{EF}=\sqrt{\mathrm{100}} \\ $$$${Cosx}=\frac{\mathrm{160}+\mathrm{180}−\mathrm{100}}{\mathrm{2}×\sqrt{\mathrm{180}×\mathrm{160}}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}} \\ $$$$\:{x}=\mathrm{45}° \\ $$ Answered by…
Question Number 226534 by ajfour last updated on 02/Dec/25 Commented by ajfour last updated on 02/Dec/25 $${If}\:{AB}=\mathrm{2}\theta,\:{find}\:{everything}! \\ $$ Commented by mr W last updated…
Question Number 226469 by ajfour last updated on 30/Nov/25 Commented by ajfour last updated on 30/Nov/25 $${Find}\:{the}\:{common}\:{area}\:{of}\:{the} \\ $$$${smaller}\:{circles}.\:{Outer}\:{square} \\ $$$${has}\:{side}\:{length}\:{s}=\mathrm{2}\:{units}. \\ $$ Answered by…