Category: Geometry

Question Number 226524 by wongb1506 last updated on 02/Dec/25 Answered by som(math1967) last updated on 02/Dec/25 $$\:\alpha=\mathrm{3}{x}\:\:\beta=\mathrm{2}{x} \\ $$$$\mathrm{5}{x}=\mathrm{90}\Rightarrow{x}=\mathrm{18}=\alpha−\beta \\ $$$$\:\:\left({D}\right) \\ $$ Terms of…

Question Number 226525 by wongb1506 last updated on 02/Dec/25 Answered by som(math1967) last updated on 02/Dec/25 $${AF}=\sqrt{\mathrm{160}}\:,{AE}=\sqrt{\mathrm{180}}\:,\:{EF}=\sqrt{\mathrm{100}} \\ $$$${Cosx}=\frac{\mathrm{160}+\mathrm{180}−\mathrm{100}}{\mathrm{2}×\sqrt{\mathrm{180}×\mathrm{160}}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}} \\ $$$$\:{x}=\mathrm{45}° \\ $$ Answered by…

Question Number 226469 by ajfour last updated on 30/Nov/25 Commented by ajfour last updated on 30/Nov/25 $${Find}\:{the}\:{common}\:{area}\:{of}\:{the} \\ $$$${smaller}\:{circles}.\:{Outer}\:{square} \\ $$$${has}\:{side}\:{length}\:{s}=\mathrm{2}\:{units}. \\ $$ Answered by…

Question Number 226447 by Tawa11 last updated on 29/Nov/25 Commented by Tawa11 last updated on 29/Nov/25 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{semi}\:\mathrm{circle}. \\ $$ Answered by mr W last updated…

Question Number 226375 by ajfour last updated on 26/Nov/25 Commented by ajfour last updated on 26/Nov/25 $${Semicircle}\:{radius}\:{is}\:{R}.\:{Square} \\ $$$${side}\:{is}\:{s}.\:{Find}\:{circle}\:{radius}\:{r}. \\ $$ Answered by fantastic2 last…