Category: Geometry

Question Number 222436 by ajfour last updated on 26/Jun/25 Commented by ajfour last updated on 26/Jun/25 https://youtu.be/xLaPcyoBv2w?si=4zzxA2kFBwZVUHdh Answered by mr W last updated on 27/Jun/25…

Question Number 222376 by ajfour last updated on 24/Jun/25 Answered by ajfour last updated on 24/Jun/25 $${Say}\:{AB}\:={s} \\ $$$${AF}={t} \\ $$$${height}\:{k} \\ $$$${horizontal}\:{projestion}\:{of}\:{CD}={h} \\ $$$$\mathrm{cos}\:\theta=\frac{{x}^{\mathrm{4}}…

Question Number 222312 by ajfour last updated on 22/Jun/25 Answered by mr W last updated on 22/Jun/25 $${QC}={DC}={AB}=\mathrm{1} \\ $$$$\frac{\mathrm{1}}{{a}}=\frac{{a}}{\:\sqrt{{a}^{\mathrm{2}} +\mathrm{1}}} \\ $$$${a}^{\mathrm{4}} −{a}^{\mathrm{2}} −\mathrm{1}=\mathrm{0}…

Question Number 222176 by cherokeesay last updated on 19/Jun/25 Answered by mr W last updated on 19/Jun/25 $$\angle{B}=\beta \\ $$$$\angle{A}=\mathrm{2}\beta \\ $$$$\angle{C}=\pi−\mathrm{3}\beta \\ $$$$\frac{{a}}{\mathrm{sin}\:\mathrm{2}\beta}=\frac{{c}}{\mathrm{sin}\:\mathrm{3}\beta}=\frac{\mathrm{25}}{\mathrm{sin}\:\beta} \\…

Question Number 221958 by ajfour last updated on 13/Jun/25 Commented by mr W last updated on 14/Jun/25 $${a}\:{may}\:{not}\:{be}\:{independent}\:{from}\:{b},\:{c}. \\ $$ Commented by ajfour last updated…