Question Number 189685 by normans last updated on 20/Mar/23 Answered by manxsol last updated on 21/Mar/23 Answered by a.lgnaoui last updated on 20/Mar/23 Commented by…
Question Number 189684 by normans last updated on 20/Mar/23 Commented by a.lgnaoui last updated on 21/Mar/23 Answered by mr W last updated on 20/Mar/23 Commented…
Question Number 189680 by normans last updated on 20/Mar/23 Commented by normans last updated on 20/Mar/23 $${sorry}\:{to}\:{Q}\mathrm{189551}. \\ $$$$\:{this}\:{is}\:{true}\:{problem}….. \\ $$ Commented by mr W…
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Question Number 58567 by olalekan2 last updated on 25/Apr/19 $$\:{A}\:{regular}\:{polygon}\:{of}\:\left(\mathrm{2}{k}+\mathrm{1}\right)\:{sides} \\ $$$${has}\:\mathrm{140}\:{as}\:{the}\:{size}\:{of}\:{each}\:{interior} \\ $$$${angle}.{Find}\:{k} \\ $$ Commented by mr W last updated on 25/Apr/19 $$\left(\mathrm{2}{k}+\mathrm{1}\right)\left(\mathrm{180}−\mathrm{140}\right)=\mathrm{360}…
Question Number 189615 by Rupesh123 last updated on 19/Mar/23 Answered by HeferH last updated on 19/Mar/23 $$\mathrm{16}−\mathrm{x}\sqrt{\mathrm{5}}\:=\:\frac{\mathrm{8x}}{\mathrm{3}\sqrt{\mathrm{5}}}−\frac{\mathrm{x}}{\:\sqrt{\mathrm{5}}} \\ $$$$\mathrm{16}−\mathrm{x}\sqrt{\mathrm{5}}\:=\:\frac{\mathrm{5x}}{\mathrm{3}\sqrt{\mathrm{5}}} \\ $$$$\:\mathrm{48}\sqrt{\mathrm{5}}\:−\:\mathrm{15x}\:=\:\mathrm{5x} \\ $$$$\:\mathrm{x}\:=\:\frac{\mathrm{48}\sqrt{\mathrm{5}}}{\mathrm{20}} \\ $$$$\mathrm{x}\sqrt{\mathrm{5}}\:=\:\frac{\mathrm{48}\centerdot\mathrm{5}}{\mathrm{20}}\:=\frac{\mathrm{48}}{\mathrm{4}}\:=\:\mathrm{12}\:…
Question Number 189608 by mr W last updated on 19/Mar/23 Commented by mr W last updated on 19/Mar/23 $${a}\:{bin}\:{has}\:{the}\:{shape}\:{of}\:{a}\:{frustum} \\ $$$${as}\:{shown}.\:{an}\:{ant}\:{climbs}\:{on}\:{the}\:{outer} \\ $$$${surface}\:{of}\:{the}\:{bin}\:{from}\:{point} \\ $$$${A}\:{to}\:{point}\:{B}\:{following}\:{a}\:{path}\:{with}…
Question Number 124076 by TANMAY PANACEA last updated on 30/Nov/20 $${intregation}…{collected}\:{problem} \\ $$ Commented by TANMAY PANACEA last updated on 30/Nov/20 Commented by TANMAY PANACEA…
Question Number 189605 by normans last updated on 19/Mar/23 Commented by mr W last updated on 19/Mar/23 $$\frac{{a}/\mathrm{4}}{\mathrm{7}}=\frac{\mathrm{9}−{a}/\mathrm{4}}{\mathrm{9}} \\ $$$$\Rightarrow{a}=\frac{\mathrm{4}×\mathrm{7}×\mathrm{9}}{\mathrm{7}+\mathrm{9}}=\frac{\mathrm{63}}{\mathrm{4}} \\ $$ Commented by normans…