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Category: Geometry

Question-189438

Question Number 189438 by normans last updated on 16/Mar/23 Answered by som(math1967) last updated on 16/Mar/23 $${construct}\:{FM}\parallel{BE} \\ $$$$\bigtriangleup{AFM}\sim\bigtriangleup{ABE} \\ $$$$\frac{{AM}}{{AE}}=\frac{\mathrm{3}}{\mathrm{3}+\mathrm{5}}=\frac{\mathrm{3}}{\mathrm{8}} \\ $$$$\frac{{AM}}{{ME}}=\frac{\mathrm{3}}{\mathrm{5}} \\ $$$${EO}\parallel{FM}…