Question Number 188845 by ajfour last updated on 07/Mar/23 Answered by a.lgnaoui last updated on 07/Mar/23 $$\bigtriangleup{OAB}\:\:\:\left({recrangle}\:{en}\:{O}\right) \\ $$$${AB}={a}+\frac{{a}\sqrt{\mathrm{2}}}{\mathrm{2}}\:\:\:\:\Rightarrow{AH}=\frac{{a}}{\mathrm{2}}+\frac{{a}\sqrt{\mathrm{2}}}{\mathrm{4}} \\ $$$${OA}={OB}\:={R} \\ $$$$\mathrm{sin}\:\frac{\pi}{\mathrm{4}}=\frac{{AH}}{{R}}\Rightarrow{R}=\frac{\mathrm{2}{AH}}{\:\sqrt{\mathrm{2}}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{{R}}=\mathrm{1}+\sqrt{\mathrm{2}}…
Question Number 188755 by normans last updated on 06/Mar/23 Commented by mr W last updated on 06/Mar/23 $${with}\:{given}\:{data}\:{the}\:{area}\:{of}\:\Delta{CFE} \\ $$$${is}\:{not}\:{uniquely}\:{defined}!\: \\ $$$${it}'{s}\:{dependent}\:{from}\:{the}\:{angle}\:\angle{A}. \\ $$ Commented…
Question Number 188701 by cortano12 last updated on 05/Mar/23 Commented by mr W last updated on 06/Mar/23 $${x}=\mathrm{15}° \\ $$ Commented by cortano12 last updated…
Question Number 188642 by normans last updated on 04/Mar/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 188635 by normans last updated on 04/Mar/23 Answered by nikif99 last updated on 05/Mar/23 $${Two}\:{solutions}\:{found}: \\ $$$${ABCDE}=\mathrm{57674}\:{or}\:\mathrm{77456} \\ $$$${so}\:{A}+{C}−{E}=\mathrm{7}\:{or}\:\mathrm{5} \\ $$ Terms of…
Question Number 188623 by normans last updated on 03/Mar/23 Commented by mr W last updated on 04/Mar/23 Commented by mr W last updated on 04/Mar/23…
Question Number 188615 by normans last updated on 03/Mar/23 Answered by HeferH last updated on 03/Mar/23 $$\mathrm{37}°? \\ $$ Commented by HeferH last updated on…
Question Number 123027 by Lekhraj last updated on 21/Nov/20 Commented by kolos last updated on 24/Nov/20 $${dude}\:,\:{how}\:{did}\:{you}\:{post}\:{a}\:{figure}?\: \\ $$ Answered by TANMAY PANACEA last updated…
Question Number 122974 by Dwaipayan Shikari last updated on 21/Nov/20 $$\underset{{k}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{tan}\left({k}\right)}{{k}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 188463 by emilagazade last updated on 01/Mar/23 Answered by mr W last updated on 01/Mar/23 $$\frac{{AO}}{{CO}}=\frac{\mathrm{sin}\:\mathrm{30}}{\mathrm{sin}\:\mathrm{70}} \\ $$$$\frac{{BO}}{{AO}}=\frac{\mathrm{sin}\:\mathrm{40}}{\mathrm{sin}\:\alpha} \\ $$$$\frac{{CO}}{{BO}}=\frac{\mathrm{sin}\:\left(\mathrm{20}−\alpha\right)}{\mathrm{sin}\:\mathrm{20}} \\ $$$$\left({i}\right)×\left({ii}\right)×\left({iii}\right): \\…