Question Number 221815 by alvan545 last updated on 11/Jun/25 Answered by mr W last updated on 11/Jun/25 $${say}\:{AC}={c} \\ $$$${BC}^{\mathrm{2}} ={CD}^{\mathrm{2}} \\ $$$${a}^{\mathrm{2}} +{c}^{\mathrm{2}} −\mathrm{2}{ac}\:\mathrm{cos}\:\theta={b}^{\mathrm{2}}…
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Question Number 221707 by Tawa11 last updated on 09/Jun/25 Commented by Tawa11 last updated on 09/Jun/25 In the ∆ABC |AB|=|BC|=|AC|=K, Area of the shaded ∆…
Question Number 221733 by Tawa11 last updated on 09/Jun/25 Commented by Tawa11 last updated on 09/Jun/25 $$\mathrm{Is}\:\:\mathrm{10}.\mathrm{37cm}\:\:\mathrm{correct}? \\ $$ Commented by ajfour last updated on…
Question Number 221637 by ASAD7391 last updated on 08/Jun/25 Answered by fantastic last updated on 09/Jun/25 $${let}\:\angle{A}=\theta\:\therefore\angle{B}=\mathrm{2}\theta\: \\ $$$${but}\:\angle{A}+\angle{B}+\angle{C}=\mathrm{180}^{\mathrm{0}} \\ $$$${or}\:\theta+\mathrm{2}\theta=\mathrm{180}^{\mathrm{0}} −\mathrm{90}^{\mathrm{0}} =\mathrm{90}^{\mathrm{0}} \\ $$$${or}\:\theta=\frac{\mathrm{90}^{\mathrm{0}}…
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Question Number 221495 by Tawa11 last updated on 06/Jun/25 Commented by Tawa11 last updated on 06/Jun/25 In the ∆ABC |AB|=|BC|=|AC|=K, Area of the shaded ∆…
Question Number 221444 by Tawa11 last updated on 05/Jun/25 Commented by Tawa11 last updated on 05/Jun/25 In the ∆ABC |AB|=|BC|=|AC|=K, Area of the shaded ∆…
Question Number 221406 by ajfour last updated on 03/Jun/25 Commented by ajfour last updated on 03/Jun/25 $${Find}\:\mathrm{tan}\:\phi\:\:\:{if}\:\mathrm{tan}\:\theta=\mathrm{1}/\mathrm{4}. \\ $$ Answered by mr W last updated…