Question Number 186883 by Mingma last updated on 11/Feb/23 Answered by HeferH last updated on 12/Feb/23 Commented by HeferH last updated on 12/Feb/23 Commented by…
Question Number 121337 by ajfour last updated on 06/Nov/20 Commented by ajfour last updated on 06/Nov/20 $${Find}\:{ratio}\:\:\frac{{s}}{{R}}\:,\:{where}\:{s}\:{is}\:{side} \\ $$$${lengths}\:{of}\:{the}\:{two}\:{equilateral} \\ $$$${triangles}\:{and}\:{R}\:{the}\:{radius}\:{of}\: \\ $$$${the}\:{semicircle}. \\ $$…
Question Number 121330 by ajfour last updated on 06/Nov/20 Commented by ajfour last updated on 06/Nov/20 $${Find}\:{ratio}\:{of}\:{coloured}\:{area}\:{to} \\ $$$${outer}\:{square}\:{area}. \\ $$ Commented by MJS_new last…
Question Number 186838 by mnjuly1970 last updated on 11/Feb/23 Answered by mr W last updated on 11/Feb/23 Commented by mr W last updated on 11/Feb/23…
Question Number 186833 by mr W last updated on 11/Feb/23 Commented by mr W last updated on 11/Feb/23 $${as}\:{Q}\mathrm{186762},\:{but}\:{the}\:{well}\:{has}\:{the}\:{shape} \\ $$$${of}\:{an}\:{ellipse}. \\ $$ Answered by…
Question Number 186809 by ajfour last updated on 10/Feb/23 Answered by ajfour last updated on 10/Feb/23 Commented by ajfour last updated on 10/Feb/23 $${x}={p}=\mathrm{tan}\:\theta,\:{let}\:\:\mathrm{tan}\:\alpha={c} \\…
Question Number 186788 by Mingma last updated on 10/Feb/23 Answered by HeferH last updated on 10/Feb/23 Commented by HeferH last updated on 10/Feb/23 $${Special}\:{quadrilateral}: \\…
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