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Category: Geometry

Question-221268

Question Number 221268 by behi834171 last updated on 29/May/25 Commented by behi834171 last updated on 29/May/25 $$\boldsymbol{{CF}}=\sqrt{\mathrm{2}}\:\:,\:\:\boldsymbol{{CD}}=\mathrm{2}\:\:\:,\:\:\:\:\boldsymbol{{CE}}=\mathrm{3} \\ $$$$\boldsymbol{{possible}}\:\boldsymbol{{value}}\left(\boldsymbol{{s}}\right)\:\boldsymbol{{for}}:\boldsymbol{{R}}=? \\ $$$$\boldsymbol{{R}}=\boldsymbol{{radius}}.\:\:\:\boldsymbol{{A}}=\boldsymbol{{center}} \\ $$ Answered by…

Question-221188

Question Number 221188 by ajfour last updated on 26/May/25 Commented by Frix last updated on 27/May/25 $$\left(\mathrm{1}\right)\:\mathrm{We}'\mathrm{re}\:\mathrm{looking}\:\mathrm{at}\:\mathrm{the}\:\mathrm{cube}\:\mathrm{diagonally} \\ $$$$\mathrm{because}\:\mathrm{the}\:\mathrm{vertexes}\:\mathrm{touch}\:\mathrm{both}\:\mathrm{the}\:\mathrm{sphere} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{cone} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{I}\:\mathrm{think}\:\mathrm{we}\:\mathrm{need}\:\mathrm{1}\:\mathrm{more}\:\mathrm{information} \\ $$…

Question-221025

Question Number 221025 by Tawa11 last updated on 22/May/25 Answered by mr W last updated on 23/May/25 $$\mathrm{20}\:{convex}\:{quadrilaterals}\:\left({red}\right) \\ $$$$\mathrm{5}\:{concave}\:{quadrilaterals}\:\left({blue}\right) \\ $$$$\mathrm{25}\:{cross}−{quadrilaterals}\:\left({green}\right) \\ $$$$\Rightarrow{totally}\:\mathrm{50}\:{quadrilaterals} \\…