Question Number 221369 by mr W last updated on 01/Jun/25 Commented by mr W last updated on 01/Jun/25 $${no} \\ $$ Commented by fantastic last…
Question Number 221370 by mr W last updated on 01/Jun/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 221268 by behi834171 last updated on 29/May/25 Commented by behi834171 last updated on 29/May/25 $$\boldsymbol{{CF}}=\sqrt{\mathrm{2}}\:\:,\:\:\boldsymbol{{CD}}=\mathrm{2}\:\:\:,\:\:\:\:\boldsymbol{{CE}}=\mathrm{3} \\ $$$$\boldsymbol{{possible}}\:\boldsymbol{{value}}\left(\boldsymbol{{s}}\right)\:\boldsymbol{{for}}:\boldsymbol{{R}}=? \\ $$$$\boldsymbol{{R}}=\boldsymbol{{radius}}.\:\:\:\boldsymbol{{A}}=\boldsymbol{{center}} \\ $$ Answered by…
Question Number 221196 by mnjuly1970 last updated on 26/May/25 Answered by mr W last updated on 27/May/25 Commented by mr W last updated on 27/May/25…
Question Number 221188 by ajfour last updated on 26/May/25 Commented by Frix last updated on 27/May/25 $$\left(\mathrm{1}\right)\:\mathrm{We}'\mathrm{re}\:\mathrm{looking}\:\mathrm{at}\:\mathrm{the}\:\mathrm{cube}\:\mathrm{diagonally} \\ $$$$\mathrm{because}\:\mathrm{the}\:\mathrm{vertexes}\:\mathrm{touch}\:\mathrm{both}\:\mathrm{the}\:\mathrm{sphere} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{cone} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{I}\:\mathrm{think}\:\mathrm{we}\:\mathrm{need}\:\mathrm{1}\:\mathrm{more}\:\mathrm{information} \\ $$…
Question Number 221170 by mr W last updated on 26/May/25 Commented by mr W last updated on 26/May/25 $${the}\:{area}\:{of}\:{the}\:{rectangle}\:{is}\:\mathrm{80}. \\ $$$${find}\:{the}\:{shaded}\:{area}. \\ $$ Answered by…
Question Number 221117 by mr W last updated on 25/May/25 Commented by mr W last updated on 25/May/25 $${find}\:{shaded}\:{area}\:=? \\ $$ Answered by fantastic last…
Question Number 221012 by mr W last updated on 22/May/25 Commented by mr W last updated on 24/May/25 $$\cancel{{yes}}\:{it}'{s}\:{not}\:{given}\:{that}\:{it}\:{is}\:{a}\:{square}. \\ $$ Commented by fantastic last…
Question Number 221025 by Tawa11 last updated on 22/May/25 Answered by mr W last updated on 23/May/25 $$\mathrm{20}\:{convex}\:{quadrilaterals}\:\left({red}\right) \\ $$$$\mathrm{5}\:{concave}\:{quadrilaterals}\:\left({blue}\right) \\ $$$$\mathrm{25}\:{cross}−{quadrilaterals}\:\left({green}\right) \\ $$$$\Rightarrow{totally}\:\mathrm{50}\:{quadrilaterals} \\…
Question Number 220832 by Nicholas666 last updated on 20/May/25 Answered by mr W last updated on 20/May/25 Answered by Spillover last updated on 20/May/25 Answered…