Question Number 183326 by Acem last updated on 25/Dec/22 Commented by Acem last updated on 25/Dec/22 $$\:{Easy}\:{quest}. \\ $$ Answered by HeferH last updated on…
Question Number 183295 by ajfour last updated on 24/Dec/22 Commented by ajfour last updated on 24/Dec/22 $${Find}\:{R}\:{in}\:{terms}\:{of}\:{a}\:{and}\:{b}. \\ $$ Answered by ajfour last updated on…
Question Number 183281 by mr W last updated on 24/Dec/22 Commented by mr W last updated on 24/Dec/22 $${find}\:{the}\:{length}\:{of}\:{AC}. \\ $$ Answered by mr W…
Question Number 52198 by ajfour last updated on 04/Jan/19 Answered by MJS last updated on 04/Jan/19 $${c}_{\mathrm{1}} :\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{4}{R}^{\mathrm{2}} \\ $$$${c}_{\mathrm{2}} :\:{x}^{\mathrm{2}} +\left({y}−{R}\right)^{\mathrm{2}} ={R}^{\mathrm{2}}…
Question Number 52190 by ajfour last updated on 04/Jan/19 Commented by ajfour last updated on 04/Jan/19 $${Or}\:{else}\:{find}\:{just}\:\theta. \\ $$ Commented by MJS last updated on…
Question Number 183254 by HeferH last updated on 24/Dec/22 Answered by TUN last updated on 24/Dec/22 $$\frac{{sin}\left(\mathrm{14}{x}\right)}{{sin}\left(\mathrm{8}{x}\right)}=\frac{{sin}\left({x}\right)}{{sin}\left(\mathrm{7}{x}\right)} \\ $$ Answered by a.lgnaoui last updated on…
Question Number 52182 by mr W last updated on 04/Jan/19 Commented by mr W last updated on 04/Jan/19 $${A}\:{container}\:{in}\:{the}\:{form}\:{of}\:{a}\:{pyramid} \\ $$$${should}\:{be}\:{formed}\:{using}\:{three}\:{steel} \\ $$$${plates}.\:{The}\:{openng}\:{is}\:{a}\:{triangle}\:{with} \\ $$$${sides}\:{a},{b},{c}.\:{The}\:{volume}\:{of}\:{the}\:{container}…
Question Number 183227 by mr W last updated on 23/Dec/22 Commented by mr W last updated on 23/Dec/22 $${find}\:{the}\:{length}\:{of}\:{other}\:{diagonal}. \\ $$ Answered by mr W…
Question Number 183216 by mr W last updated on 23/Dec/22 Commented by mr W last updated on 23/Dec/22 Commented by mr W last updated on…
Question Number 52129 by ajfour last updated on 03/Jan/19 Commented by ajfour last updated on 03/Jan/19 $${Find}\:{radius}\:\boldsymbol{{r}}\:{of}\:{circles}\:\left({the}\:{same}\right) \\ $$$${in}\:{terms}\:{of}\:{square}\:{side}\:\boldsymbol{{a}}. \\ $$ Commented by ajfour last…