Question Number 182546 by Acem last updated on 11/Dec/22 Commented by Acem last updated on 11/Dec/22 $${Modify}:\:{Find}\:{the}\:{greatest}\:{and}\:{the}\:{least}\:{angles} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{in}\:{rad}. \\ $$ Answered by Rasheed.Sindhi last…
Question Number 51466 by mr W last updated on 27/Dec/18 Commented by mr W last updated on 27/Dec/18 $${A}\:{rod}\:{of}\:{length}\:{b}\:{and}\:{mass}\:{M}\:{is} \\ $$$${hanging}\:{at}\:{both}\:{ends}\:{with}\:{two}\:{ropes} \\ $$$${on}\:{the}\:{ceiling},\:{see}\:{picture}.\:{One}\:{rope} \\ $$$${is}\:{of}\:{length}\:{l}_{\mathrm{1}}…
Question Number 182533 by Acem last updated on 10/Dec/22 $${If}\:{you}\:{walk}\:{around}\:{a}\:{triangle}\:{with}\:{sides}\:\mathrm{3},\:\mathrm{6},\:\mathrm{8} \\ $$$${respectively}\:{such}\:{a}\:{way}\:{that}\:{you}\:{keep}\:{a}\:{distance} \\ $$$$\:{of}\:\mathrm{3}{m}\:{from}\:{it},\:{then}\: \\ $$$$\:{how}\:{much}\:{distance}\:{will}\:{you}\:{travel}? \\ $$ Answered by mr W last updated on…
Question Number 182532 by Acem last updated on 10/Dec/22 $${Q}.\mathrm{181494} \\ $$$$\:{Let}'{s}\:{try}\:{it} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 182500 by mr W last updated on 10/Dec/22 Commented by mr W last updated on 10/Dec/22 $${this}\:{time}\:{our}\:{goat}\:{is}\:{flexibly}\:{tied}\:{on} \\ $$$${a}\:{fence}\:{with}\:{a}\:{rope}\:{of}\:{length}\:\mathrm{3}{m}.\:{the} \\ $$$${fence}\:{has}\:{the}\:{shape}\:{of}\:{an}\:{ellipse}\:{with} \\ $$$${semi}−{axex}\:{of}\:\mathrm{10}\:{m}\:{and}\:\mathrm{6}\:{m}\:{respectively}.…
Question Number 51422 by ajfour last updated on 26/Dec/18 Commented by ajfour last updated on 26/Dec/18 $${Find}\:{R}\:{the}\:{radius}\:{of}\:{semicircle} \\ $$$${in}\:{terms}\:{of}\:{radii}\:{a}\:{and}\:{b}\:{of}\:{the} \\ $$$${circles}. \\ $$ Answered by…
Question Number 182472 by Acem last updated on 10/Dec/22 $${If}\:{you}\:{walk}\:{around}\:{a}\:{triangle}\:\mathrm{4}{m}\:{each}\:{side}\:{such} \\ $$$$\:{a}\:{way}\:{that}\:{you}\:{keep}\:{a}\:{distance}\:{of}\:\mathrm{2}{m}\:{from}\:{it},\:{then} \\ $$$${how}\:{much}\:{distance}\:{will}\:{you}\:{travel}? \\ $$ Answered by mr W last updated on 10/Dec/22 Commented…
Question Number 182474 by Acem last updated on 10/Dec/22 $${Find}\:{the}\:{number}\:{of}\:{sides}\:{of}\:{two}\:{regular}\:{polygons} \\ $$$$\:{that}\:{their}\:{sides}\:{has}\:{a}\:{ratio}\:\mathrm{5}:\mathrm{4}\:{and}\:{of}\:\mathrm{9}°\:{as}\:{a} \\ $$$$\:{difference}\:{between}\:{their}\:{angles}. \\ $$ Answered by mr W last updated on 10/Dec/22 $${n}−{sided}\:{regular}\:{polygon}:…
Question Number 182407 by Acem last updated on 09/Dec/22 Answered by a.lgnaoui last updated on 09/Dec/22 $${Area}=\mathrm{AC}×\mathrm{AB}\frac{\mathrm{sin}\:\beta}{\mathrm{2}} \\ $$$$\beta=\frac{\mathrm{12}}{\mathrm{5}}\:\mathrm{x}\:\:\:\gamma=\frac{\mathrm{3x}}{\mathrm{2}}\:\:\:\alpha=\frac{\mathrm{3}}{\mathrm{5}}\mathrm{x}\:\:\:\left({degre}\right) \\ $$$$\alpha+\beta+\gamma=\mathrm{180}\:\:\:\left(\:\frac{\mathrm{45}}{\mathrm{10}}\right)×\mathrm{x}=\mathrm{180}\:\:\mathrm{x}=\mathrm{40} \\ $$$$\beta=\frac{\mathrm{12}×\mathrm{40}}{\mathrm{5}}=\mathrm{96}° \\ $$$${Area}=\frac{\mathrm{2}×\mathrm{AB}}{\mathrm{2}}×\mathrm{sin}\:\mathrm{96}…
Question Number 182392 by Acem last updated on 08/Dec/22 Commented by Acem last updated on 08/Dec/22 $$\:{Prove}:\:\frac{\mathrm{1}}{\:\sqrt{{a}}}=\:\frac{\mathrm{1}}{\:\sqrt{{b}}}\:+\:\frac{\mathrm{1}}{\:\sqrt{{c}}} \\ $$ Answered by HeferH last updated on…