Category: Geometry

Question Number 116466 by mr W last updated on 04/Oct/20 Commented by mr W last updated on 04/Oct/20 $${R}={radius}\:{of}\:{big}\:{circles} \\ $$$${r}={radius}\:{of}\:{small}\:{circles} \\ $$$${let}\:\lambda=\frac{{r}}{{R}} \\ $$$$\mathrm{cos}\:\alpha=\frac{{R}}{{R}+{r}}=\frac{\mathrm{1}}{\mathrm{1}+\lambda}…

Question Number 181987 by Acem last updated on 03/Dec/22 Answered by Frix last updated on 03/Dec/22 $$\left.\frac{\mathrm{sin}\:\mathrm{45}°}{{BC}}=\frac{\mathrm{sin}\:\mathrm{105}°}{{AC}}=\frac{\mathrm{sin}\:\mathrm{30}°}{{AB}}\right) \\ $$$$\Rightarrow\frac{{BC}}{{AC}}=\sqrt{\mathrm{3}}−\mathrm{1} \\ $$$${AC}+{BC}=\mathrm{14}\:\mathrm{it}'\mathrm{s}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{get} \\ $$$${AC}=\frac{\mathrm{14}\sqrt{\mathrm{3}}}{\mathrm{3}}\wedge{BC}=\frac{\mathrm{14}\left(\mathrm{3}−\sqrt{\mathrm{3}}\right)}{\mathrm{3}}\:\Rightarrow\:{AB}=\frac{\mathrm{7}\sqrt{\mathrm{2}}\left(\mathrm{3}−\sqrt{\mathrm{3}}\right)}{\mathrm{3}} \\ $$…

Question Number 116413 by soumyasaha last updated on 03/Oct/20 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 181918 by HeferH last updated on 02/Dec/22 Answered by Acem last updated on 02/Dec/22 Commented by Acem last updated on 02/Dec/22 $${Sir}\:{HeferH},\:{share}\:{with}\:{me}\:{to}\:{find}\:{x}\:{cause} \\…

Question Number 181869 by mnjuly1970 last updated on 01/Dec/22 Commented by mr W last updated on 01/Dec/22 $${see}\:{Q}\mathrm{180582} \\ $$ Terms of Service Privacy Policy…