Category: Geometry

Question Number 220264 by Tawa11 last updated on 10/May/25 Answered by SdC355 last updated on 10/May/25 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\underset{{h}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{\left(\mathrm{2}{h}+\mathrm{9}\right)\left(\mathrm{2}{h}+\mathrm{11}\right)} \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\underset{{h}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{1}}{\mathrm{2}{h}+\mathrm{9}}−\frac{\mathrm{1}}{\mathrm{2}{h}+\mathrm{11}}\right)=\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{1}}{\mathrm{11}}−\frac{\mathrm{1}}{\mathrm{13}}+\frac{\mathrm{1}}{\mathrm{13}}−\frac{\mathrm{1}}{\mathrm{15}}+….\right)…

Question Number 220263 by Tawa11 last updated on 10/May/25 Answered by mr W last updated on 10/May/25 $${blue}=\left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{2}} ×{red} \\ $$$${pink}={green} \\ $$$${blue}+{pink}+{red}+{green}=\mathrm{24}.\mathrm{5} \\ $$$${blue}+{pink}=\frac{\mathrm{3}}{\mathrm{4}}\left({red}+{green}\right)…

Question Number 220113 by Spillover last updated on 05/May/25 Answered by Spillover last updated on 06/May/25 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 220114 by Spillover last updated on 05/May/25 Answered by mr W last updated on 06/May/25 Commented by mr W last updated on 06/May/25…

Question Number 220108 by Spillover last updated on 05/May/25 Answered by mr W last updated on 06/May/25 $$\frac{{xh}_{\mathrm{1}} }{\mathrm{2}}={b}\:\Rightarrow{xh}_{\mathrm{1}} =\mathrm{2}{b} \\ $$$$\left(\frac{{h}_{\mathrm{2}} }{{h}_{\mathrm{1}} }\right)^{\mathrm{2}} =\frac{{a}}{{b}}\:\Rightarrow{h}_{\mathrm{2}}…