Question Number 47881 by behi83417@gmail.com last updated on 16/Nov/18 Commented by behi83417@gmail.com last updated on 16/Nov/18 $$\measuredangle{A}=\mathrm{90}^{\bullet} ,{AB}=\mathrm{6},{AC}=\mathrm{8},{AD}={AE}=\mathrm{3}.\mathrm{6} \\ $$$$\rightarrow\measuredangle{BFC}=?,{areaB}\overset{\bigtriangleup} {{F}C}=? \\ $$ Terms of…
Question Number 178947 by HeferH last updated on 23/Oct/22 Answered by mr W last updated on 23/Oct/22 Commented by mr W last updated on 23/Oct/22…
Question Number 47824 by ajfour last updated on 15/Nov/18 Commented by ajfour last updated on 15/Nov/18 $${Find}\:{the}\:{equation}\:{of}\:{the}\:{shadow} \\ $$$${curve}\:{of}\:{a}\:{sphere}\:{of}\:{radius}\:{R} \\ $$$${mounted}\:{on}\:{a}\:{pole}\:{of}\:{height}\:{h}. \\ $$ Commented by…
Question Number 178884 by mr W last updated on 22/Oct/22 Commented by mr W last updated on 22/Oct/22 $${a}\:{goat}\:{is}\:{tied}\:{at}\:{a}\:{point}\:{on}\:{the}\:{foot}\:{of} \\ $$$${a}\:{hill}\:{which}\:{has}\:{the}\:{shape}\:{of}\:{a}\:{sphere}\: \\ $$$${with}\:{radius}\:\mathrm{60}{m}\:{and}\:\:{height}\:\mathrm{20}{m}\:{as}\: \\ $$$${shown}.\:{the}\:{length}\:{of}\:{the}\:{rope}\:{is}\:\mathrm{20}{m}.…
Question Number 47788 by behi83417@gmail.com last updated on 14/Nov/18 Commented by behi83417@gmail.com last updated on 14/Nov/18 $${ABCD}:{square}. \\ $$$$\measuredangle{AEC}=\theta,\measuredangle{BED}=\varphi. \\ $$$${show}\:{that}:\:\:\:\:\frac{{S}_{{B}\overset{\blacktriangle} {{E}D}} }{{S}_{{A}\overset{\blacktriangle} {{E}C}} }=\frac{{tg}\varphi}{{tg}\theta}…
Question Number 47779 by ajfour last updated on 14/Nov/18 Commented by mr W last updated on 14/Nov/18 $${best}\:{illustration}\:{for}\:{this}\:{question}\:{sir}! \\ $$ Terms of Service Privacy Policy…
Question Number 47775 by behi83417@gmail.com last updated on 14/Nov/18 Commented by behi83417@gmail.com last updated on 14/Nov/18 $$\boldsymbol{\mathrm{ABC}}:{equilateral}. \\ $$$${distance}\:{of}\:\boldsymbol{\mathrm{D}}{from}:\boldsymbol{\mathrm{F}},\boldsymbol{\mathrm{E}},\boldsymbol{\mathrm{C}}=\mathrm{2},\mathrm{3},\mathrm{6} \\ $$$$\left({respectively}\right) \\ $$$$\rightarrow…..\boldsymbol{\mathrm{AB}}=? \\ $$…
Question Number 178824 by a.lgnaoui last updated on 21/Oct/22 $$\:\measuredangle\mathrm{BCD}=\mathrm{45}^{°} \:\:\:\mathrm{BD}=\mathrm{6};\:\:\mathrm{AD}=\mathrm{1} \\ $$$${Determiner}\:\mathrm{AE}?\:\:\mathrm{AC}? \\ $$ Commented by a.lgnaoui last updated on 21/Oct/22 $$\measuredangle\mathrm{CAD}=\mathrm{90}° \\ $$…
Question Number 47735 by behi83417@gmail.com last updated on 14/Nov/18 Commented by mr W last updated on 14/Nov/18 $${we}\:{only}\:{need}\:{to}\:{know}\:{the}\:{distances}\:{to} \\ $$$${three}\:{vertexes}.\:{the}\:{distance}\:{to}\:{the} \\ $$$${fourth}\:{vertex}\:{is}\:{not}\:{independent}. \\ $$ Commented…
Question Number 47713 by ajfour last updated on 13/Nov/18 Commented by ajfour last updated on 13/Nov/18 $${If}\:{cylinder}\:{has}\:{length}\:{L},\:{find} \\ $$$${how}\:{much}\:{area}\:{of}\:{cylinder} \\ $$$${receives}\:{light}\:{from}\:{the}\:{point} \\ $$$${source}\:{at}\:{a}\:{distance}\:{d}\:{and}\:{at} \\ $$$${same}\:{level}\:{h}={R}\:{as}\:{its}\:{axis}.…