Question Number 220103 by Spillover last updated on 05/May/25 Answered by efronzo1 last updated on 06/May/25 $$\:\:\mathrm{tan}\:\beta\:=\:\frac{{a}−\mathrm{1}}{\mathrm{1}}\:=\:\frac{{a}}{\mathrm{1}}\:\Rightarrow{a}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\:\:\mathrm{tan}\:\beta\:=\:\frac{\mathrm{1}}{\mathrm{2}}\:\Rightarrow\mathrm{tan}\:\mathrm{2}\beta\:=\:\frac{\mathrm{1}}{\mathrm{1}−\frac{\mathrm{1}}{\mathrm{4}}}\:=\:\frac{\mathrm{4}}{\mathrm{3}} \\ $$$$\:\:\alpha−\beta\:=\:\alpha+\beta−\mathrm{2}\beta \\ $$$$\:\:\mathrm{tan}\:\left(\alpha−\beta\right)\:=\:\frac{\mathrm{tan}\:\left(\alpha+\beta\right)−\mathrm{tan}\:\mathrm{2}\beta}{\mathrm{1}+\mathrm{tan}\:\left(\alpha+\beta\right).\:\mathrm{tan}\:\mathrm{2}\beta} \\ $$…
Question Number 219948 by Spillover last updated on 04/May/25 Answered by Spillover last updated on 04/May/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 219949 by Spillover last updated on 04/May/25 Answered by vnm last updated on 04/May/25 $$\mathrm{Let}\:{AH}=\mathrm{1}\:\mathrm{be}\:\mathrm{the}\:\mathrm{altitude}\:\mathrm{of}\: \\ $$$$\mathrm{triangle}\:{ABC} \\ $$$$\measuredangle{BAH}=\mathrm{60}°,\:\measuredangle{MAH}=\mathrm{45}°−{y} \\ $$$$\measuredangle{CAH}=\mathrm{75}°,\:\measuredangle{NAH}=\mathrm{45}°+{y} \\ $$$$\mathrm{tan}\:\mathrm{60}°−\mathrm{tan}\:\left(\mathrm{45}°−{y}\right)=\mathrm{tan}\:\mathrm{75}°−\mathrm{tan}\:\left(\mathrm{45}°+{y}\right)…
Question Number 219944 by Spillover last updated on 04/May/25 Answered by som(math1967) last updated on 04/May/25 $${Red}\:{area}=\frac{\mathrm{1}}{\mathrm{2}}\pi×\mathrm{6}^{\mathrm{2}} −\left(\frac{\mathrm{1}}{\mathrm{4}}\pi×\mathrm{6}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{6}^{\mathrm{2}} \right) \\ $$$$\:+\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{12}×\mathrm{12}−\left(\frac{\mathrm{1}}{\mathrm{4}}\pi×\mathrm{6}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{6}^{\mathrm{2}} \right) \\…
Question Number 219945 by Spillover last updated on 04/May/25 Answered by mr W last updated on 04/May/25 Commented by mr W last updated on 04/May/25…
Question Number 219946 by Spillover last updated on 04/May/25 Answered by Spillover last updated on 04/May/25 Answered by Spillover last updated on 04/May/25 Terms of…
Question Number 219921 by Spillover last updated on 03/May/25 Answered by mr W last updated on 04/May/25 Commented by mr W last updated on 04/May/25…
Question Number 219917 by Spillover last updated on 03/May/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 219918 by Spillover last updated on 03/May/25 Commented by Spillover last updated on 04/May/25 Commented by Spillover last updated on 04/May/25 Answered by…
Question Number 219919 by Spillover last updated on 03/May/25 Answered by Spillover last updated on 04/May/25 Answered by Spillover last updated on 04/May/25 Answered by…