Category: Geometry

Question Number 111539 by Aina Samuel Temidayo last updated on 04/Sep/20 $$\mathrm{In}\:\mathrm{a}\:\mathrm{trapezoid}\:\mathrm{ABCD},\:\mathrm{sides}\:\mathrm{AB}\:\mathrm{and} \\ $$$$\mathrm{CD}\:\mathrm{are}\:\mathrm{parallel}\:\mathrm{and}\:\mathrm{side}\:\mathrm{BC}=\mathrm{CD}=\sqrt{\mathrm{5}}. \\ $$$$\mathrm{If}\:\mathrm{D}\hat {\mathrm{C}B}\:=\mathrm{120}°\:\mathrm{and}\:\mathrm{B}\hat {\mathrm{A}D}=\mathrm{60}°.\:\mathrm{Find} \\ $$$$\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{ABCD}. \\ $$ Answered by 1549442205PVT…

Question Number 111497 by bemath last updated on 04/Sep/20 Commented by kaivan.ahmadi last updated on 04/Sep/20 $${let}\:{t}={x}_{\mathrm{1}} ^{\mathrm{3}} +\mathrm{6}{x}_{\mathrm{1}} ^{\mathrm{2}} −\mathrm{30}{x}_{\mathrm{1}} +{x}_{\mathrm{1}} ^{\mathrm{2}} {x}_{\mathrm{2}} −\mathrm{5}{x}_{\mathrm{1}}…

Question Number 111477 by Aina Samuel Temidayo last updated on 03/Sep/20 $$\mathrm{Triangle}\:\mathrm{ABC}\:\mathrm{has}\:\mathrm{AB}=\mathrm{2}\centerdot\mathrm{AC}.\:\mathrm{Let} \\ $$$$\mathrm{D}\:\mathrm{and}\:\mathrm{E}\:\mathrm{be}\:\mathrm{on}\:\mathrm{AB}\:\mathrm{and}\:\mathrm{BC} \\ $$$$\mathrm{respectively}\:\mathrm{such}\:\mathrm{that}\:\angle\mathrm{BAE} \\ $$$$=\angle\mathrm{ACD}.\:\mathrm{Let}\:\mathrm{F}\:\mathrm{be}\:\mathrm{the}\:\mathrm{intersections}\:\mathrm{of} \\ $$$$\mathrm{segments}\:\mathrm{AE}\:\mathrm{and}\:\mathrm{CD},\:\mathrm{and}\:\mathrm{suppose} \\ $$$$\mathrm{that}\:\bigtriangleup\mathrm{CFE}\:\mathrm{is}\:\mathrm{equilateral}.\:\mathrm{What}\:\mathrm{is} \\ $$$$\angle\mathrm{ACB}? \\…

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Question Number 111432 by ajfour last updated on 03/Sep/20 Commented by ajfour last updated on 03/Sep/20 $${Find}\:{perimeter}\:{of}\:\bigtriangleup{OAB}. \\ $$ Commented by ajfour last updated on…