Question Number 45690 by ajfour last updated on 15/Oct/18 Commented by ajfour last updated on 15/Oct/18 $${Radius}\:{of}\:{circle}\:{is}\:{unity}. \\ $$$${Find}\:{b}\:{in}\:{terms}\:{of}\:{a}. \\ $$ Answered by MrW3 last…
Question Number 176741 by HeferH last updated on 26/Sep/22 $$\: \\ $$$$\:{In}\:{the}\:{following}\:{figure},\:{if}\:\:\:\frac{{S}_{\mathrm{1}} \:+{S}_{\mathrm{2}} }{\:\sqrt{{S}_{\mathrm{3}} }}\:=\:\frac{\mathrm{6}}{\:\sqrt{\pi}} \\ $$$$\:{find}\:{the}\:{area}\:{of}\:{the}\:{circular}\:{crown}\: \\ $$$$\: \\ $$ Commented by HeferH last…
Question Number 111187 by ajfour last updated on 02/Sep/20 Commented by ajfour last updated on 03/Sep/20 $${Find}\:{sides}\:{AB}\:{and}\:{BC}\:{of}\:{rectangle}.\:\:\: \\ $$ Answered by ajfour last updated on…
Question Number 45630 by ajfour last updated on 14/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 15/Oct/18 $$\frac{\mathrm{1}}{\mathrm{2}}×{l}×{x}=\sqrt{{s}\left({s}−{a}\right)\left({s}−{b}\right)\left({s}−{c}\right)}\: \\ $$$${s}=\frac{{R}+{x}+{x}+{r}+{l}}{\mathrm{2}}={x}+\frac{{R}+{r}+{l}}{\mathrm{2}} \\ $$$${a}={R}+{x}\:\:\:\:{b}={x}+{r}\:\:\:\:{c}={l} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}{lx}=\sqrt{\left({x}+\frac{{R}+{r}+{l}}{\mathrm{2}}\right)\left(\frac{{r}+{l}+{R}}{\mathrm{2}}−{R}\right)\left(\frac{{R}+{l}+{r}}{\mathrm{2}}−{r}\right)\left({x}+\frac{{R}+{r}+{l}}{\mathrm{2}}−{l}\right)}\: \\ $$$$\frac{{l}^{\mathrm{2}}…
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Question Number 111135 by ajfour last updated on 02/Sep/20 Answered by mr W last updated on 02/Sep/20 $$\mathrm{2}{r}+{R}−\sqrt{{R}^{\mathrm{2}} −{r}^{\mathrm{2}} }=\mathrm{2}{R} \\ $$$$\mathrm{2}{r}−{R}=\sqrt{{R}^{\mathrm{2}} −{r}^{\mathrm{2}} } \\…
Question Number 176531 by a.lgnaoui last updated on 20/Sep/22 $${Dans}\:{la}\:{figure}\:{ci}−{joint} \\ $$$${AB}\mid\mid\:{A}^{'} {B}^{'} \:\:\:{AA}^{'} ={BB}^{'} ={CC}^{'} \\ $$$${Determiner}\:{le}\:{rapport} \\ $$$$\:\:\:\:\:\frac{{aire}\:\Delta\left({A}^{'} {B}^{'} {C}^{'} \right)}{{aire}\:\Delta\left({ABC}\right)}=? \\ $$…
Question Number 45448 by MrW3 last updated on 13/Oct/18 Commented by MrW3 last updated on 13/Oct/18 $${When}\:{an}\:{ellipse}\:{is}\:{rotated}\:{by}\:{an} \\ $$$${angle}\:\alpha,\:{the}\:{five}\:{partial}\:{areas}\:{are}\:{equal}. \\ $$$${Find}\:{the}\:{equation}\:{of}\:{the}\:{ellipse} \\ $$$${for}\:\alpha=\mathrm{90}°\:{and}\:\mathrm{45}°\:{respectively}. \\ $$…
Question Number 45427 by ajfour last updated on 12/Oct/18 Commented by ajfour last updated on 12/Oct/18 $${Determine}\:{side}\:\boldsymbol{{a}}\:{of}\:{square}, \\ $$$${without}\:{using}\:{calculator}. \\ $$ Commented by ajfour last…
Question Number 45381 by behi83417@gmail.com last updated on 12/Oct/18 Commented by behi83417@gmail.com last updated on 12/Oct/18 $$\angle{ABN}=\angle{NBO}=\angle{OBC}=\frac{\angle{ABC}}{\mathrm{3}} \\ $$$$\angle{BAN}=\angle{NAC},\angle{ACO}=\angle{OCB} \\ $$$${AB}=\mathrm{12},{BC}=\mathrm{8},{AC}=\mathrm{10} \\ $$$${Q}#\mathrm{1}={radius}\:{of}\:{red}\:\:{circle}. \\ $$$${Q}#\mathrm{2}={area}\:{of}\:\:{N}\overset{\lozenge}…