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Category: Geometry

Question-45122

Question Number 45122 by MrW3 last updated on 09/Oct/18 Commented by MrW3 last updated on 09/Oct/18 $${A}\:{mountain}\:{has}\:{the}\:{shape}\:{of}\:{a}\:{semi} \\ $$$${sphere}\:{with}\:{radius}\:{R}.\:{From}\:{a}\:{point}\:{A} \\ $$$${at}\:{the}\:{foot}\:{of}\:{mountain}\:{to}\:{a}\:{point}\:{B}\: \\ $$$${over}\:{point}\:{A}\:{two}\:{paths}\:{will}\:{be}\:{built}. \\ $$$${One}\:{path}\:{should}\:{have}\:{the}\:{shortest}…

Q-in-AB-C-A-90-o-and-m-b-2-m-c-2-100-find-the-value-of-a-note-m-a-the-median-corresponding-

Question Number 176100 by mnjuly1970 last updated on 12/Sep/22 $$ \\ $$$$\:\:\:\:\:{Q}\:: \\ $$$$\:\:\:\:\:{in}\:\:{A}\overset{\Delta} {{B}C}\::\:{A}\:=\:\mathrm{90}^{\mathrm{o}} \:\:\:{and}\:,\:{m}_{\:{b}} ^{\mathrm{2}} \:+\:{m}_{\:{c}} ^{\:\mathrm{2}} \:=\:\mathrm{100}.\:\:\:\:\:\:\:\:\: \\ $$$$\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{find}\:\:{the}\:\:{value}\:{of}\:\:\:''\:\:\:{a}\:\:\:''\:. \\…

Question-176086

Question Number 176086 by amin96 last updated on 11/Sep/22 Commented by mahdipoor last updated on 11/Sep/22 $$?=\frac{\mathrm{1}}{\mathrm{2}{cosa}}\approx\mathrm{1}.\mathrm{4142} \\ $$$${a}={tan}^{−\mathrm{1}} \left(\frac{{sin}\frac{\mathrm{720}}{\mathrm{7}}+{sin}\frac{\mathrm{360}}{\mathrm{7}}−\mathrm{4}{sin}\left(\frac{\mathrm{90}}{\mathrm{7}}\right){sin}\left(\frac{\mathrm{900}}{\mathrm{7}}\right)}{{cos}\frac{\mathrm{360}}{\mathrm{7}}+{cos}\frac{\mathrm{720}}{\mathrm{7}}}\right) \\ $$$$ \\ $$ Terms…

Question-175717

Question Number 175717 by ajfour last updated on 05/Sep/22 Answered by mr W last updated on 05/Sep/22 $$\left({R}−{r}\right)^{\mathrm{2}} ={r}^{\mathrm{2}} +\left(\frac{{R}}{\mathrm{2}}+{r}\right)^{\mathrm{2}} \\ $$$${r}^{\mathrm{2}} +\mathrm{3}{Rr}−\frac{\mathrm{3}{R}^{\mathrm{2}} }{\mathrm{4}}=\mathrm{0} \\…

Question-44636

Question Number 44636 by Raj Singh last updated on 02/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 02/Oct/18 $${join}\:{oB}\:{andOC} \\ $$$$\bigtriangleup{OAB}\:{and}\:{OAC}\: \\ $$$$\left.\mathrm{1}\right){OB}={OC}\:\left({radius}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\…

Question-44621

Question Number 44621 by Tawa1 last updated on 02/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 02/Oct/18 $$\left.{a}\right){sector}\:{area}\:{s}=\frac{\pi{r}^{\mathrm{2}} }{\mathrm{2}\pi}×\theta=\frac{{r}^{\mathrm{2}} \theta}{\mathrm{2}} \\ $$$$\mathrm{132}=\frac{\mathrm{12}×\mathrm{12}}{\mathrm{2}}×\theta \\ $$$$\theta=\frac{\mathrm{132}×\mathrm{2}}{\mathrm{12}×\mathrm{12}}=\frac{\mathrm{11}}{\mathrm{6}} \\ $$$${l}={r}\theta…