Category: Geometry

Question Number 108868 by ajfour last updated on 19/Aug/20 Commented by ajfour last updated on 19/Aug/20 $${Find}\:{b}/{a}. \\ $$ Answered by ajfour last updated on…

Question Number 174370 by behi834171 last updated on 30/Jul/22 Commented by behi834171 last updated on 31/Jul/22 $$\:\:\:\:\:\:\:{AH}={HE},{BI}={ID},{CG}={GF} \\ $$$$\:\:\:\:\:\:\:\boldsymbol{{area}}\:\boldsymbol{{of}}\:\boldsymbol{{A}}\overset{\blacktriangle} {\boldsymbol{{B}C}}=\sqrt{\mathrm{2}}\:\:\:\:\:\:\boldsymbol{{units}} \\ $$$$\:\:\:\:\:\:\:\boldsymbol{{area}}\:\boldsymbol{{of}}:\boldsymbol{{H}}\overset{\blacktriangle} {\boldsymbol{{I}G}}=?\:\:\:\:\:\:\:\:\:\boldsymbol{{units}} \\ $$…

Question Number 43263 by MrW3 last updated on 09/Sep/18 Answered by MJS last updated on 09/Sep/18 $${AB}\:\mathrm{is}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{line}\:\mathrm{on}\:\mathrm{the}\:\mathrm{mantle} \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{plain} \\ $$$${C}=\begin{pmatrix}{\mathrm{0}}\\{\mathrm{0}}\end{pmatrix} \\ $$$$\mathrm{angle}\:{ACB}\:=\frac{{r}}{{s}}\mathrm{360}°=\frac{\mathrm{20}}{\mathrm{60}}\mathrm{360}°=\mathrm{120}° \\ $$$$\mathrm{circle}\:\mathrm{A}…

Question Number 174315 by mnjuly1970 last updated on 29/Jul/22 Answered by aleks041103 last updated on 29/Jul/22 $${if}\:{the}\:{intersection}\:{point}\:{on}\:{AB}\:{is}\:{O}, \\ $$$${let}'{s}\:{set}\:{its}\:{coordinates}\:{to}\:\left(\mathrm{0},\mathrm{0}\right) \\ $$$${then}\:{OB}\:{is}\:{the}\:{x}\:{axis}. \\ $$$${then}\:{th}\:{equation}\:{of}\:{the}\:{slanted}\:{line}\:{is}: \\ $$$${y}={x}…

Question Number 43205 by Tawa1 last updated on 08/Sep/18 Answered by $@ty@m last updated on 08/Sep/18 $$\because\angle{SRQ}=\angle{RTS}\:\left({alternate}\:{segment}\:{theorem}\right) \\ $$$$\therefore\angle{SRQ}=\mathrm{28}^{\mathrm{o}} \\ $$$${We}\:{have} \\ $$$$\angle{VRM}+\angle{VRS}+\angle{SRQ}=\mathrm{180}^{\mathrm{o}} \\ $$$$\Rightarrow\mathrm{46}^{\mathrm{o}}…