Question Number 174218 by dragan91 last updated on 27/Jul/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 43135 by MrW3 last updated on 07/Sep/18 $${Construct}\:{a}\:{triangle}\:\Delta{ABC}\:{with} \\ $$$$\angle{B}=\mathrm{50}° \\ $$$${AC}=\mathrm{6}\:{cm} \\ $$$${AB}+{BC}=\mathrm{8}\:{cm} \\ $$$$ \\ $$$${see}\:{also}\:{Q}\mathrm{42942}. \\ $$ Commented by math1967…
Question Number 174185 by nadovic last updated on 26/Jul/22 $$\mathrm{The}\:\mathrm{circle}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{2}{x}−\mathrm{4}{y}−\mathrm{20}=\mathrm{0}\:\mathrm{is} \\ $$$$\mathrm{inscribed}\:\mathrm{in}\:\mathrm{a}\:\mathrm{square}.\:\mathrm{One}\:\mathrm{vertex} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{square}\:\mathrm{is}\:\left(−\mathrm{4},\:\mathrm{7}\right).\:\mathrm{Find}\:\mathrm{the} \\ $$$$\mathrm{coordinates}\:\mathrm{of}\:\mathrm{the}\:\mathrm{other}\:\mathrm{vertices}. \\ $$ Answered by Cesar1994 last updated…
Question Number 108626 by I want to learn more last updated on 18/Aug/20 Answered by Aziztisffola last updated on 18/Aug/20 $$\mathrm{A}_{\frac{\mathrm{1}}{\mathrm{2}}\mathrm{circle}} =\frac{\mathrm{1}}{\mathrm{2}}\pi\left(\frac{\mathrm{a}}{\mathrm{2}}\right)^{\mathrm{2}} =\frac{\pi\mathrm{a}^{\mathrm{2}} }{\mathrm{8}} \\…
Question Number 174094 by nadovic last updated on 24/Jul/22 $$\mathrm{The}\:\mathrm{circles}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{2}{ax}+\mathrm{8}{y}+\mathrm{13}=\mathrm{0} \\ $$$$\mathrm{and}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}{by}+\mathrm{1}=\mathrm{0}\:\mathrm{are}\: \\ $$$$\mathrm{congruent}.\:\mathrm{If}\:\mathrm{they}\:\mathrm{are}\:\mathrm{2}\sqrt{\mathrm{10}}\:\mathrm{units}\: \\ $$$$\mathrm{apart},\:\mathrm{find}\:\mathrm{the}\:\mathrm{possible}\:\mathrm{values}\:\mathrm{of} \\ $$$${a}\:\mathrm{and}\:{b}. \\ $$ Answered…
Question Number 108538 by I want to learn more last updated on 17/Aug/20 Commented by Rasheed.Sindhi last updated on 17/Aug/20 $${See}\:{Q}#\mathrm{108483} \\ $$ Terms of…
Question Number 42948 by ajfour last updated on 05/Sep/18 Commented by ajfour last updated on 05/Sep/18 $${Find}\:{coordinates}\:{of}\:{point}\:{P}\:,\:{if} \\ $$$${the}\:{coloured}\:{area}\:{is}\:{a}\:{minimum}. \\ $$ Commented by MJS last…
Question Number 108483 by I want to learn more last updated on 17/Aug/20 Commented by Rasheed.Sindhi last updated on 17/Aug/20 Commented by Rasheed.Sindhi last updated…
Question Number 42942 by Raj Singh last updated on 05/Sep/18 Answered by MJS last updated on 05/Sep/18 $${BC}={a}\:\:{CA}={b}\:\:{AB}={c} \\ $$$$ \\ $$$$\mathrm{1}.\:{a}=\mathrm{6}\:\:\beta=\mathrm{50}°\:\:{b}+{c}=\mathrm{8}\:\Rightarrow\:{c}=\mathrm{8}−{b} \\ $$$$\alpha+\gamma=\mathrm{130}°\:\Rightarrow\:\gamma=\mathrm{130}°−\alpha \\…
Question Number 108474 by pticantor last updated on 17/Aug/20 $$\boldsymbol{{U}}_{\boldsymbol{{n}}} =\underset{{k}=\mathrm{0}} {\overset{\mathrm{2}{n}−\mathrm{1}} {\sum}}\frac{\mathrm{1}}{\mathrm{2}{n}+{k}}=? \\ $$$$\boldsymbol{{li}}\underset{\boldsymbol{{n}}>\infty} {\boldsymbol{{m}U}}_{{n}} =? \\ $$ Answered by Dwaipayan Shikari last updated…