Question Number 108068 by I want to learn more last updated on 14/Aug/20 Answered by Sarah85 last updated on 14/Aug/20 $$\mathrm{a}\:\mathrm{triangle}\:\mathrm{is}\:\mathrm{given}\:\mathrm{with} \\ $$$${a}=\sqrt{\mathrm{2}^{\mathrm{2}} +\mathrm{3}^{\mathrm{3}} }=\sqrt{\mathrm{13}}…
Question Number 108067 by I want to learn more last updated on 14/Aug/20 Answered by 1549442205PVT last updated on 14/Aug/20 Commented by 1549442205PVT last updated…
Question Number 42352 by Raj Singh last updated on 24/Aug/18 Answered by tanmay.chaudhury50@gmail.com last updated on 24/Aug/18 $$\angle{AOC}=\angle{BOD}=\mathrm{2}{x}\:\left({vertically}\:{opposite}\:{angle}\:{voa}\right) \\ $$$$\angle{AOB}=\angle{COD}\:\:=\mathrm{2}{y}\left({voa}\right) \\ $$$$\mathrm{2}{x}+\mathrm{2}{y}+\mathrm{2}{x}+\mathrm{2}{y}=\mathrm{360}^{{o}} \\ $$$${x}+{y}+{x}+{y}=\mathrm{180}^{{o}} \\…
Question Number 173408 by mr W last updated on 11/Jul/22 Commented by mr W last updated on 11/Jul/22 $${the}\:{areas}\:{of}\:{three}\:{parts}\:{of}\:{a}\:{regular} \\ $$$${hexagon}\:{are}\:{given}.\:{find}\:{the}\:{areas}\:{of} \\ $$$${the}\:{other}\:{parts}. \\ $$…
Question Number 42310 by ajfour last updated on 23/Aug/18 Commented by ajfour last updated on 23/Aug/18 $${Solution}\:{to}\:{Q}.\mathrm{41766}\:\left({Another}\:{method}\right) \\ $$ Answered by ajfour last updated on…
Question Number 173273 by mr W last updated on 09/Jul/22 Commented by mr W last updated on 09/Jul/22 $${find}\:{the}\:{maximum}\:{area}\:{of}\:{green} \\ $$$${inscribed}\:{circle}=? \\ $$ Answered by…
Question Number 173275 by mr W last updated on 09/Jul/22 Commented by mr W last updated on 09/Jul/22 $${find}\:{the}\:{blue}\:{shaded}\:{area}=? \\ $$ Answered by mahdipoor last…
Question Number 42154 by ajfour last updated on 19/Aug/18 Commented by ajfour last updated on 19/Aug/18 $${If}\:\:{r}\:<\:\boldsymbol{\rho}\:<{R}\:\:{where}\:{r}\:{means} \\ $$$${inradius},\:{and}\:{R}\:{the}\:{cirumradius} \\ $$$${of}\:\bigtriangleup{ABC},\:{then}\:{locate}\:{centre}\:{S} \\ $$$${of}\:{given}\:{circle}\:{inside}\:{triangle} \\ $$$$\left({using}\:{a},{b},{c},\:{and}\:\rho\right)…
Question Number 42112 by Raj Singh last updated on 18/Aug/18 Commented by Raj Singh last updated on 18/Aug/18 $${if}\:{OF}\:{and}\:{OE}\:{is}\:{bisector}\:{of}\:<{BOC} \\ $$$${and}\:<{AOC}\:{and}\:{OE}\:{perpendicalr} \\ $$$${to}\:{OF}\:\:{then}\:{prove}\:{that}\:{A}\:{O}\:{B}\:{is}\:{linear} \\ $$…
Question Number 107634 by I want to learn more last updated on 11/Aug/20 Answered by Rasheed.Sindhi last updated on 12/Aug/20 $$\:\ulcorner\:: \\ $$$${Area}\:{of}\:{cross}\:{section} \\ $$$$\mathrm{1}×\mathrm{5}+\mathrm{1}×\mathrm{5}=\mathrm{10}\:{cm}^{\mathrm{2}}…