Question Number 42045 by tanmay.chaudhury50@gmail.com last updated on 17/Aug/18 $${i}\:{have}\:{some}\:{thing}\:{to}\:{say}…{in}\:{this}\:{platform}\:\:{several} \\ $$$${people}/{students}/{others}\:{post}\:{questions}..{others} \\ $$$${take}\:{promt}\:{action}\:{to}\:{solve}\:{the}\:{problems}.. \\ $$$${after}\:{the}\:{problem}\:{got}\:{solved}..{the}\:{person}/{students} \\ $$$${who}\:{post}\:{questions}\:{never}\:{attend}\:{or}\:{see}\:{the}\:{answer} \\ $$$${even}\:{do}\:{not}\:{clarify}\:{whether}\:{the}\:{answer}\:{is}\:{right} \\ $$$${or}\:{wrong}…{or}\:{whether}\:{he}/{she}\:{got}\:{understood}\:{the} \\ $$$${method}…{so}\:{pls}\:{show}\:{your}\:{courtsey}\:{otherwise} \\…
Question Number 107572 by ajfour last updated on 11/Aug/20 Commented by ajfour last updated on 11/Aug/20 $${The}\:{cones}\:{have}\:{base}\:{radius}\:{r}\:{and} \\ $$$${semi}-{vertical}\:{angle}\:\alpha/\mathrm{2}.\:{Find} \\ $$$${radius}\:{of}\:{the}\:{pink}\:{sphere}\:{that} \\ $$$${touches}\:{the}\:{cones}\:{externally}\:{and} \\ $$$${touches}\:{the}\:{plane}\:{passing}\:{through}…
Question Number 107537 by I want to learn more last updated on 11/Aug/20 Commented by Sarah85 last updated on 11/Aug/20 $$\mathrm{volume}=\mathrm{area}\:\mathrm{of}\:\mathrm{base}×\mathrm{length} \\ $$ Commented by…
Question Number 173032 by mnjuly1970 last updated on 05/Jul/22 Answered by mr W last updated on 05/Jul/22 Commented by mr W last updated on 05/Jul/22…
Question Number 173025 by mnjuly1970 last updated on 05/Jul/22 Answered by mr W last updated on 06/Jul/22 Commented by mr W last updated on 06/Jul/22…
Question Number 173026 by mnjuly1970 last updated on 05/Jul/22 Answered by mr W last updated on 05/Jul/22 Commented by mr W last updated on 05/Jul/22…
Question Number 107415 by ajfour last updated on 10/Aug/20 Commented by ajfour last updated on 10/Aug/20 $${Find}\:\:{r}/{R}. \\ $$ Answered by mr W last updated…
Question Number 172918 by mnjuly1970 last updated on 03/Jul/22 Commented by som(math1967) last updated on 03/Jul/22 $$\boldsymbol{{yes}}\:\boldsymbol{{i}}\:\boldsymbol{{got}}\:\frac{\mathrm{16}}{\mathrm{3}}\boldsymbol{{cm}} \\ $$ Commented by infinityaction last updated on…
Question Number 41787 by Tawa1 last updated on 12/Aug/18 Answered by tanmay.chaudhury50@gmail.com last updated on 12/Aug/18 $${grey}\:{area}={ya}\:+\frac{\mathrm{1}}{\mathrm{2}}\left({x}−{y}\right){a} \\ $$$$=\frac{\mathrm{2}{ya}+{xa}−{ya}}{\mathrm{2}} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}\left({x}+{y}\right){a} \\ $$ Terms of…
Question Number 41766 by ajfour last updated on 12/Aug/18 Answered by MrW3 last updated on 18/Aug/18 $${let}'{s}\:{say}\:\mathrm{0}<{b}\leqslant{a}\leqslant\mathrm{2}{R} \\ $$$$ \\ $$$${B}\left(\mathrm{0},\mathrm{0}\right) \\ $$$${O}\left(\frac{{b}}{\mathrm{2}},\sqrt{{R}^{\mathrm{2}} −\frac{{b}^{\mathrm{2}} }{\mathrm{4}}}\right)…