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Category: Geometry

Question-219425

Question Number 219425 by Nicholas666 last updated on 24/Apr/25 Commented by Nicholas666 last updated on 24/Apr/25 $$\:\:\:\:{ABC}\:{reguler}\:{pentagon}\: \\ $$$$\:\:\:{P},\:{Q},\:{T}\:\:\:\:\:{toricelli}'{s}\:{point}\:{of}\:{AED},{BCD},{ADE}\:\:\:\:\: \\ $$$$\:\:\:{find}\:{angle}\:{PTQ}? \\ $$ Answered by…

Question-219339

Question Number 219339 by Spillover last updated on 23/Apr/25 Answered by mr W last updated on 23/Apr/25 $$\alpha=\mathrm{45}°+\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\mathrm{tan}\:\alpha=\frac{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}}{\mathrm{1}−\mathrm{1}×\frac{\mathrm{1}}{\mathrm{2}}}=\mathrm{3} \\ $$ Answered by…