Category: Geometry

Question Number 172763 by mnjuly1970 last updated on 01/Jul/22 Answered by aleks041103 last updated on 01/Jul/22 Commented by aleks041103 last updated on 01/Jul/22 $$\left.\mathrm{1}\right) \\…

Question Number 172723 by mnjuly1970 last updated on 30/Jun/22 Answered by mr W last updated on 30/Jun/22 $$\mathrm{tan}\:\alpha=\frac{\mathrm{3}}{\mathrm{4}}=\frac{\mathrm{2}\:\mathrm{tan}\:\frac{\alpha}{\mathrm{2}}}{\mathrm{1}−\mathrm{tan}^{\mathrm{2}} \:\frac{\alpha}{\mathrm{2}}} \\ $$$$\left(\mathrm{3}\:\mathrm{tan}\:\frac{\alpha}{\mathrm{2}}−\mathrm{1}\right)\left(\mathrm{tan}\:\frac{\alpha}{\mathrm{2}}+\mathrm{3}\right)=\mathrm{0} \\ $$$$\Rightarrow\mathrm{tan}\:\frac{\alpha}{\mathrm{2}}=\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\mathrm{5}{r}+\frac{{r}}{\mathrm{tan}\:\frac{\alpha}{\mathrm{2}}}=\mathrm{4}…

Question Number 41620 by Tawa1 last updated on 10/Aug/18 Commented by Tawa1 last updated on 10/Aug/18 $$\mathrm{If}\:\mathrm{each}\:\mathrm{of}\:\mathrm{the}\:\mathrm{small}\:\mathrm{circles}\:\mathrm{in}\:\mathrm{the}\:\mathrm{diagram}\:\mathrm{has}\:\mathrm{the}\:\mathrm{radius}\:=\:\mathrm{r}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{large}\:\mathrm{circle}\:\mathrm{in}\:\mathrm{terms}\:\mathrm{of}\:\mathrm{r} \\ $$ Answered by MrW3 last…

Question Number 172628 by mnjuly1970 last updated on 29/Jun/22 Commented by mr W last updated on 29/Jun/22 $${maybe}\:\frac{\mathrm{2}}{\mathrm{tan}\:\gamma}=\frac{\mathrm{1}}{\mathrm{tan}\:\beta}−\frac{\mathrm{1}}{\mathrm{tan}\:\alpha}\:? \\ $$ Commented by mnjuly1970 last updated…

Question Number 172558 by bagjagugum123 last updated on 28/Jun/22 Answered by mr W last updated on 28/Jun/22 Commented by mr W last updated on 28/Jun/22…