Question Number 24604 by sastry last updated on 22/Nov/17 $${x}^{\mathrm{2}} −{x}\mathrm{sin}\:{x}−\mathrm{cos}\:{x}=\mathrm{0} \\ $$ Answered by jota last updated on 22/Nov/17 $${Graficando}\:{x}\approx\mathrm{1}.\mathrm{21}\:{o}\:−\mathrm{1}.\mathrm{21} \\ $$ Answered by…
Question Number 155673 by amin96 last updated on 03/Oct/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 155657 by mr W last updated on 03/Oct/21 Commented by mr W last updated on 03/Oct/21 $${Q}\mathrm{154594} \\ $$ Answered by mr W…
Question Number 155628 by amin96 last updated on 03/Oct/21 Answered by mr W last updated on 03/Oct/21 $${BM}={MC}=\mathrm{1} \\ $$$${AC}=\mathrm{2}\sqrt{\mathrm{2}} \\ $$$$\frac{\mathrm{1}}{\mathrm{cos}\:\left(\mathrm{45}+{x}\right)\:\mathrm{sin}\:\mathrm{30}}=\frac{\mathrm{2}\sqrt{\mathrm{2}}}{\mathrm{sin}\:\left(\mathrm{30}+{x}\right)} \\ $$$$\frac{\mathrm{1}}{\mathrm{cos}\:{x}−\mathrm{sin}\:{x}}=\frac{\mathrm{2}}{\mathrm{cos}\:{x}+\sqrt{\mathrm{3}}\:\mathrm{sin}\:{x}} \\…
Question Number 90069 by ajfour last updated on 21/Apr/20 Commented by ajfour last updated on 21/Apr/20 $${dont}\:{know}\:{why}\:{i}\:{get}\:{two}\:{answers}; \\ $$$$\frac{{r}}{{R}}\:\approx\:\mathrm{0}.\mathrm{49172},\:\mathrm{0}.\mathrm{39253} \\ $$ Commented by ajfour last…
Question Number 90058 by mr W last updated on 21/Apr/20 Commented by mr W last updated on 21/Apr/20 $${find}\:\frac{{b}}{{a}}=?\:{if}\:\Delta{PQR}\:{is}\:{equilateral} \\ $$ Answered by ajfour last…
Question Number 155573 by amin96 last updated on 02/Oct/21 Commented by amin96 last updated on 02/Oct/21 $$\varphi=\frac{\mathrm{1}+\sqrt{\mathrm{5}}}{\mathrm{2}}\:\:{golden}\:{ratio} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 90011 by I want to learn more last updated on 20/Apr/20 Commented by mr W last updated on 21/Apr/20 $${x}\:\mathrm{sin}\:\frac{{a}}{\mathrm{2}}=\frac{{x}^{\mathrm{2}} }{\mathrm{2}} \\ $$$$\mathrm{sin}\:\frac{{a}}{\mathrm{2}}=\frac{{x}}{\mathrm{2}}…
Question Number 89950 by student work last updated on 20/Apr/20 Commented by Tony Lin last updated on 20/Apr/20 $${a}=\mathrm{10},{b}=\mathrm{6},{c}=\sqrt{\mathrm{10}^{\mathrm{2}} −\mathrm{6}^{\mathrm{2}} }=\mathrm{8} \\ $$$${AA}^{'} =\mathrm{2}{a}=\mathrm{20} \\…
Question Number 155426 by ajfour last updated on 30/Sep/21 Commented by talminator2856791 last updated on 30/Sep/21 $$\: \\ $$$$\:\:\mathrm{30}:\mathrm{60}:\mathrm{90}\: \\ $$$$\:\Rightarrow\:{OE}\:=\:\sqrt{\mathrm{3}} \\ $$$$\: \\ $$…