Question Number 153977 by mr W last updated on 12/Sep/21 Answered by mr W last updated on 12/Sep/21 $$\frac{{l}}{{a}}=\frac{\mathrm{sin}\:\left(\mathrm{45}+\alpha\right)}{\mathrm{sin}\:\alpha}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\left(\frac{\mathrm{1}}{\mathrm{tan}\:\alpha}+\mathrm{1}\right) \\ $$$$\frac{\mathrm{1}}{\mathrm{tan}\:\alpha}=\frac{\sqrt{\mathrm{2}}{l}}{{a}}−\mathrm{1} \\ $$$${similarly} \\ $$$$\frac{\mathrm{1}}{\mathrm{tan}\:\beta}=\frac{\sqrt{\mathrm{2}}{l}}{{b}}−\mathrm{1}…
Question Number 22896 by jazary last updated on 23/Oct/17 $${how}\:{can}\:{demonstred} \\ $$$$\mathrm{17}^{\mathrm{4}{n}+\mathrm{1}} +\mathrm{3}×\mathrm{9}^{\mathrm{2}{n}+\mathrm{1}} \equiv\mathrm{0}\left[\mathrm{11}\right] \\ $$ Commented by Rasheed.Sindhi last updated on 24/Oct/17 $$\mathrm{For}\:\mathrm{n}=\mathrm{1} \\…
Question Number 88378 by Rio Michael last updated on 10/Apr/20 $$\:\mathrm{find}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{a}\:\mathrm{parabola}\:\mathrm{with}\:\mathrm{focus}\:\left(\mathrm{3},\mathrm{3}\right) \\ $$$$\mathrm{and}\:\mathrm{directrix}\:\:{y}\:=\:\mathrm{0} \\ $$ Commented by john santu last updated on 10/Apr/20 $${o}\:{yes}.\:{should}\:{be}\:{a}\:{vertex}\: \\…
Question Number 153901 by mr W last updated on 11/Sep/21 Commented by mr W last updated on 12/Sep/21 $$\left.\mathrm{1}\right)\:{find}\:\left({ab}\right)_{{max}} =? \\ $$$$\left.\mathrm{2}\right)\:{prove}\:{that}\:{S}_{\mathrm{1}} ={S}_{\mathrm{2}} . \\…
Question Number 88349 by ajfour last updated on 10/Apr/20 Commented by ajfour last updated on 10/Apr/20 $${If}\:{both}\:{circles}\:{have}\:{equal}\:{radius}, \\ $$$${and}\:{that}\:{they}\:{touch}\:{each}\:{other} \\ $$$${and}\:{line}\:{SP}\:\:{at}\:{the}\:{same}\:{point}\:{T}, \\ $$$${then}\:{determine}\:{the}\:{sector}\:\angle,\:\alpha. \\ $$…
Question Number 22787 by vajpaithegrate@gmail.com last updated on 22/Oct/17 $$\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{sin}\:\mathrm{10}\right)=\mathrm{10}\:\mathrm{or}\:\mathrm{3}\pi−\mathrm{10} \\ $$$$\mathrm{Ans}\:\mathrm{is}\:\mathrm{3}\pi−\mathrm{10}\:\:\:\mathrm{How} \\ $$ Commented by mrW1 last updated on 22/Oct/17 $$\mathrm{by}\:\mathrm{definition}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:\mathrm{sin}^{−\mathrm{1}} \:\left(\mathrm{x}\right)\:\mathrm{is}\:\left[−\frac{\pi}{\mathrm{2}},\:+\frac{\pi}{\mathrm{2}}\right] \\…
Question Number 88306 by TawaTawa1 last updated on 09/Apr/20 Commented by mr W last updated on 10/Apr/20 $${please}\:{try}\:{again}.\:{it}'{s}\:{so}\:{obvious},\:{just} \\ $$$${connect}\:{the}\:{centers}\:{of}\:{both}\:{circles}. \\ $$ Commented by mr…
Question Number 88289 by Power last updated on 09/Apr/20 Commented by ajfour last updated on 09/Apr/20 $${this}\:{has}\:{been}\:{solved}\:{before}.. \\ $$ Commented by Power last updated on…
Question Number 88272 by ajfour last updated on 09/Apr/20 Commented by ajfour last updated on 09/Apr/20 $${Find}\:{radius}\:{of}\:{semicircle}\:{in} \\ $$$${terms}\:{of}\:{ellipse}\:{parameters} \\ $$$${a}\:{and}\:{b}.\:\:\left({a}>{b}\right) \\ $$ Answered by…
Question Number 22661 by ajfour last updated on 21/Oct/17 Commented by ajfour last updated on 21/Oct/17 $${Q}.\mathrm{22657}\:\left({solution}\:;\:{here}\:\:{becoz}\right. \\ $$$$\:\:\:\:\:\left({images}\:{from}\:{my}\:{cellphone}\right. \\ $$$$\:\:\:\:\:{gets}\:{uploaded}\:{only}\:{as}\:{new}\: \\ $$$$\:\:\:\:\:\:{question},\:{and}\:{rarely}\:{as}\:{ans} \\ $$$$\left.\:\:\:\:\:\:{or}\:{comment}\right).…