Question Number 21228 by Tinkutara last updated on 16/Sep/17 $$\mathrm{Let}\:{P}\:\mathrm{be}\:\mathrm{an}\:\mathrm{interior}\:\mathrm{point}\:\mathrm{of}\:\mathrm{a}\:\mathrm{triangle} \\ $$$${ABC}\:\mathrm{whose}\:\mathrm{sidelengths}\:\mathrm{are}\:\mathrm{26},\:\mathrm{65},\:\mathrm{78}. \\ $$$$\mathrm{The}\:\mathrm{line}\:\mathrm{through}\:{P}\:\mathrm{parallel}\:\mathrm{to}\:{BC}\:\mathrm{meets} \\ $$$${AB}\:\mathrm{in}\:{K}\:\mathrm{and}\:{AC}\:\mathrm{in}\:{L}.\:\mathrm{The}\:\mathrm{line}\:\mathrm{through} \\ $$$${P}\:\mathrm{parallel}\:\mathrm{to}\:{CA}\:\mathrm{meets}\:{BC}\:\mathrm{in}\:{M}\:\mathrm{and}\:{BA} \\ $$$$\mathrm{in}\:{N}.\:\mathrm{The}\:\mathrm{line}\:\mathrm{through}\:{P}\:\mathrm{parallel}\:\mathrm{to}\:{AB} \\ $$$$\mathrm{meets}\:{CA}\:\mathrm{in}\:{S}\:\mathrm{and}\:{CB}\:\mathrm{in}\:{T}.\:\mathrm{If}\:{KL},\:{MN}, \\ $$$${ST},\:\mathrm{are}\:\mathrm{of}\:\mathrm{equal}\:\mathrm{lengths},\:\mathrm{find}\:\mathrm{this} \\…
Question Number 152204 by cherokeesay last updated on 26/Aug/21 Commented by Paradoxical last updated on 26/Aug/21 Commented by cherokeesay last updated on 26/Aug/21 $${Nice}\:! \\…
Question Number 21001 by srinivasaraododda88@gmail.com last updated on 10/Sep/17 $$\begin{vmatrix}{{a}\:\mathrm{1}\:\mathrm{1}}\\{\mathrm{1}\:{b}\:\mathrm{1}}\\{\mathrm{1}\:\mathrm{1}\:{c}}\end{vmatrix}>\mathrm{0}\:{then}\:{showthat}\:{abc}>−\mathrm{8}−\mathrm{99} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 86528 by TawaTawa1 last updated on 29/Mar/20 Commented by TawaTawa1 last updated on 29/Mar/20 $$\mathrm{Student}\:\mathrm{sir}. \\ $$ Commented by jagoll last updated on…
Question Number 20977 by alex041103 last updated on 09/Sep/17 $${Imtegrate}\:\int{e}^{−{ax}^{\mathrm{2}} +{bx}+{c}} {dx}\:{for}\:{a}>\mathrm{0}. \\ $$$${It}'{s}\:{just}\:{for}\:{fun}.\:{If}\:{you}\:{have}\:{questions} \\ $$$${leave}\:{a}\:{comment}.\:{I}'{ll}\:{do}\:{my}\:{best}\:{to}\:{answer}\:{them}. \\ $$ Commented by alex041103 last updated on 10/Sep/17…
Question Number 20953 by tawa tawa last updated on 09/Sep/17 Commented by Tinkutara last updated on 09/Sep/17 $$\mid\mathrm{BG}\mid=\sqrt{\mathrm{l}^{\mathrm{2}} +\mathrm{w}^{\mathrm{2}} +\mathrm{h}^{\mathrm{2}} } \\ $$ Commented by…
Question Number 20944 by tawa tawa last updated on 08/Sep/17 Answered by dioph last updated on 09/Sep/17 Commented by dioph last updated on 09/Sep/17 $${r}\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\:=\:\mathrm{7}\sqrt{\mathrm{3}}\:\Rightarrow\:{r}\:=\:\mathrm{14}\:\mathrm{cm}…
Question Number 86453 by TawaTawa1 last updated on 28/Mar/20 Commented by john santu last updated on 28/Mar/20 $$\mathrm{2a}\:=\:\mathrm{distance}\:\mathrm{the}\:\mathrm{centre}\:\mathrm{point}\:\mathrm{of} \\ $$$$\mathrm{two}\:\mathrm{circle}? \\ $$ Commented by TawaTawa1…
Question Number 151973 by ajfour last updated on 24/Aug/21 Commented by ajfour last updated on 24/Aug/21 $${OB}={OC}=\sqrt{{OA}}\:\:;\:{OM}=\mathrm{1} \\ $$$${yellow}\:{area}=\mathrm{1}/\mathrm{4}\:,\:{then}\:{find} \\ $$$${OB}={OC}\:={x}\:\:\:{or}\:\:{OA}={x}^{\mathrm{2}} . \\ $$ Answered…
Question Number 151961 by Tawa11 last updated on 24/Aug/21 Commented by Tawa11 last updated on 24/Aug/21 $$\mathrm{The}\:\mathrm{pencils}\:\mathrm{has}\:\mathrm{diameter}\:\:\:\mathrm{7mm}. \\ $$$$ \\ $$$$\mathrm{Question} \\ $$Seven pencils are…