Question Number 218021 by mnjuly1970 last updated on 26/Mar/25 Answered by mr W last updated on 27/Mar/25 Commented by mr W last updated on 27/Mar/25…
Question Number 218013 by Tawa11 last updated on 25/Mar/25 Answered by mr W last updated on 26/Mar/25 $$\left.{a}\right) \\ $$$${AP}={BP}={l}=\sqrt{\mathrm{1}^{\mathrm{2}} +\mathrm{2}.\mathrm{4}^{\mathrm{2}} }=\mathrm{2}.\mathrm{6}\:{m} \\ $$$${l}_{\mathrm{0}} =\mathrm{2}\:{m}…
Question Number 217912 by malwan last updated on 23/Mar/25 $$ \\ $$ Commented by malwan last updated on 23/Mar/25 $$ \\ $$ Commented by malwan…
Question Number 217931 by CrispyXYZ last updated on 23/Mar/25 $$\mathrm{Given}\:\mathrm{a}\:\mathrm{regular}\:\mathrm{triangle}\:{ABC}. \\ $$$${AG}=\mathrm{2}{GC}.\:{CK}=\mathrm{2}{KB}.\:{AK}\cap{BG}={M}. \\ $$$$\mathrm{Prove}\:\mathrm{that}\:{CM}\bot{AK}. \\ $$ Commented by CrispyXYZ last updated on 23/Mar/25 Answered by…
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Question Number 217686 by mnjuly1970 last updated on 18/Mar/25 Commented by mnjuly1970 last updated on 18/Mar/25 $$\:\:\:\:\:{why}\:\:\:\:\:\:{BC}={CF}\:\:?\:\:\:\:\Uparrow\Uparrow\Uparrow \\ $$$$\:\:\:\:\:\:\:{and}\:\:{find}\:{the}\:{value}\:{of}\:\:\:\:''\:{x}\:''. \\ $$ Commented by mr W…
Question Number 217631 by mnjuly1970 last updated on 17/Mar/25 Commented by mnjuly1970 last updated on 17/Mar/25 $$\:{yes}\:.\:{that}'{s}\:{right}.{thanks}\:{alot}\:{sir} \\ $$ Answered by maths2 last updated on…
Question Number 217633 by lmcp1203 last updated on 17/Mar/25 Commented by mr W last updated on 17/Mar/25 $${insufficient}\:{information}\:{to}\: \\ $$$${determine}\:{x}\:{uniquely}! \\ $$ Commented by lmcp1203…
Question Number 217519 by Ari last updated on 15/Mar/25 Commented by Ari last updated on 15/Mar/25 $${Find}\:\:{x}\: \\ $$ Answered by mr W last updated…
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