Question Number 12499 by tawa last updated on 23/Apr/17 $$\mathrm{Water}\:\mathrm{flows}\:\mathrm{out}\:\mathrm{of}\:\mathrm{a}\:\mathrm{tank}\:\mathrm{through}\:\mathrm{a}\:\mathrm{hole}\:\mathrm{of}\:\mathrm{diameter}\:\mathrm{2cm}\:\mathrm{above}\:\mathrm{the}\:\mathrm{hole} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{Determine}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{outflow} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{The}\:\mathrm{rate}\:\mathrm{of}\:\mathrm{outflow}\:\mathrm{when}\:\mathrm{the}\:\mathrm{level}\:\mathrm{of}\:\mathrm{the}\:\mathrm{water}\:\mathrm{in}\:\mathrm{the}\:\mathrm{tank}\:\mathrm{is}\:\mathrm{2cm}\:\mathrm{above} \\ $$$$\mathrm{the}\:\mathrm{hole}.\: \\ $$ Answered by sandy_suhendra last updated on 24/Apr/17…
Question Number 78027 by ajfour last updated on 13/Jan/20 Commented by ajfour last updated on 13/Jan/20 $${Determine}\:{the}\:{radius}\:{in}\:{c}. \\ $$ Answered by MJS last updated on…
Question Number 12490 by narendra last updated on 23/Apr/17 $$\mathrm{328976}/\mathrm{256} \\ $$ Commented by geovane10math last updated on 24/Apr/17 $$\frac{\mathrm{328976}}{\mathrm{256}}\:=\:\mathrm{1285},\mathrm{0625} \\ $$ Terms of Service…
Question Number 77988 by ajfour last updated on 12/Jan/20 Commented by ajfour last updated on 12/Jan/20 $${If}\:{the}\:{central}\:{rectangle}\:{has} \\ $$$${has}\:{sides}\:{half}\:{of}\:{that}\:{of}\:{outer} \\ $$$${one},\:{then}\:{find}\:{AB}. \\ $$ Answered by…
Question Number 77966 by mr W last updated on 12/Jan/20 Answered by john santu last updated on 12/Jan/20 $${ratio}\:{area}\:=\:\mathrm{4}\::\:\mathrm{9}\::\:\mathrm{49}\: \\ $$$${ratio}\:{of}\:{side}\:=\:\mathrm{2}:\mathrm{3}:\mathrm{7} \\ $$$${area}\:{ABC}\:=\:\mathrm{36}×\mathrm{4}\:=\:\mathrm{144} \\ $$…
Question Number 143463 by Dwaipayan Shikari last updated on 14/Jun/21 $$\underset{{k}=\mathrm{1}} {\overset{{n}} {\prod}}{tan}\left(\frac{{k}\pi}{\mathrm{2}{n}+\mathrm{1}}\right)=\sqrt{\mathrm{2}{n}+\mathrm{1}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 12371 by JAZAR last updated on 20/Apr/17 $${tank}\:{you} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 12332 by frank ntulah last updated on 19/Apr/17 $$\mathrm{prove}\:;\:\left(\frac{\mathrm{0}}{\mathrm{0}}\right)=\mathrm{2} \\ $$ Commented by FilupS last updated on 20/Apr/17 $$\frac{\mathrm{0}}{\mathrm{0}}=\mathrm{undefined} \\ $$ Commented by…
Question Number 12267 by tawa last updated on 17/Apr/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{nth}\:\mathrm{term}\:\mathrm{of}\:\mathrm{the}\:\mathrm{sequence} \\ $$$$\left.\mathrm{1}\right)\:\:\:\frac{\mathrm{1}}{\mathrm{3}}\:,\:\frac{\mathrm{1}}{\mathrm{15}}\:,\:\frac{\mathrm{1}}{\mathrm{35}}\:,\:\frac{\mathrm{1}}{\mathrm{63}}\:,\:\frac{\mathrm{1}}{\mathrm{99}} \\ $$$$\left.\mathrm{2}\right)\:\:\:\:\frac{\mathrm{1}}{\mathrm{2}},\:\frac{\mathrm{1}}{\mathrm{6}},\:\frac{\mathrm{1}}{\mathrm{12}},\:\frac{\mathrm{1}}{\mathrm{20}},\:\frac{\mathrm{1}}{\mathrm{30}} \\ $$ Answered by ajfour last updated on 17/Apr/17 $$\left.\mathrm{1}\right)\:\:{T}_{{n}} =\frac{\mathrm{1}}{\mathrm{4}{n}^{\mathrm{2}}…
Question Number 12265 by frank ntulah last updated on 17/Apr/17 $${Determinant}\:{method}\:{can}\:{be}\:{used}\:{to}\:{solve} \\ $$$${the}\:{system}\:{below}?,\:\mathrm{if}\:\mathrm{yes}\:\mathrm{solve}\:\mathrm{by}\:\mathrm{determinant}\:\mathrm{method}\:\mathrm{and} \\ $$$$\:\mathrm{if}\:\mathrm{no}\:\mathrm{solve}\:\mathrm{by}\:\mathrm{another}\:\mathrm{method} \\ $$$$\:\:\:\:\:\:\:\:\: \\ $$$${x}+{y}−{z}=\mathrm{8} \\ $$$$\mathrm{2}{x}+{y}−\mathrm{2}{z}=\mathrm{3} \\ $$$$\left({give}\:{clear}\:{reason}\:{for}\:{your}\:{answer}\right) \\ $$…