Question Number 142164 by Panacea last updated on 27/May/21 Commented by Panacea last updated on 27/May/21 $${plse}\:{sol} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 11078 by 3494 last updated on 10/Mar/17 $$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$ Answered by FilupS last updated on 11/Mar/17…
Question Number 76585 by Crabby89p13 last updated on 28/Dec/19 Commented by john santu last updated on 28/Dec/19 $${ratio}\:{blue}\:{area}\:{to}\:{red}\:=\:\mathrm{1}\::\:\mathrm{1} \\ $$ Answered by john santu last…
Question Number 141983 by Panacea last updated on 25/May/21 Commented by Panacea last updated on 25/May/21 $$\mathrm{plse}\:\mathrm{sol}… \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 10829 by Saham last updated on 26/Feb/17 $$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\int_{\:\mathrm{1}} ^{\:\mathrm{x}} \:\:\:\frac{\mathrm{e}^{\mathrm{t}^{\mathrm{2}} } \:\left(\mathrm{dt}\right)}{\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{1}}\: \\ $$$$\left(\mathrm{a}\right)\:\mathrm{1}\:\left(\mathrm{b}\right)\:\mathrm{0}\:\left(\mathrm{c}\right)\:\mathrm{e}/\mathrm{2}\:\left(\mathrm{d}\right)\:\mathrm{e} \\ $$ Answered by bahmanfeshki last updated…
Question Number 10815 by fariraihmudzengerere75@gmail.c last updated on 26/Feb/17 $${Evalute}\:\:\int\left({x}^{\mathrm{2}\:} \:\:+\:\mathrm{9}\right)^{\mathrm{9}} \:{dx}\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10760 by Saham last updated on 24/Feb/17 $$\mathrm{A}\:\mathrm{block}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{2}.\mathrm{0kg}\:\mathrm{resting}\:\mathrm{on}\:\mathrm{a}\:\mathrm{smooth}\:\mathrm{horizontal}\:\mathrm{plane}\:\mathrm{is}\:\mathrm{acted} \\ $$$$\mathrm{upon}\:\mathrm{simultaneously}\:\mathrm{by}\:\mathrm{two}\:\mathrm{forces}\:\mathrm{10N}\:\mathrm{due}\:\mathrm{north}\:\mathrm{and}\:\mathrm{10N}\:\mathrm{due}\:\mathrm{east}. \\ $$$$\mathrm{The}\:\mathrm{magnitude}\:\mathrm{of}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{produce}\:\mathrm{by}\:\mathrm{the}\:\mathrm{force}\:\mathrm{on}\:\mathrm{the}\:\mathrm{block}. \\ $$ Commented by chux last updated on 24/Feb/17 $$\mathrm{please}\:\mathrm{are}\:\mathrm{you}\:\mathrm{a}\:\mathrm{nigerian} \\…
Question Number 141750 by Algoritm last updated on 23/May/21 Answered by cherokeesay last updated on 23/May/21 $$\frac{\pi\left(\mathrm{2}{r}\right)^{\mathrm{2}} }{\mathrm{4}}\:−\:\pi{r}^{\mathrm{2}} \:\Leftrightarrow\:\frac{\pi\mathrm{4}{r}^{\mathrm{2}} }{\mathrm{4}}\:−\:\pi{r}^{\mathrm{2}} \:=\:\mathrm{0} \\ $$$$\frac{{B}_{{Area}} }{{R}_{{Area}} }\:=\:\mathrm{1}…
Question Number 10667 by Gaurav3651 last updated on 22/Feb/17 $${prove}\:{that}\:{the}\:{quadrilateral}\:{formed} \\ $$$${by}\:{angle}\:{bisectors}\:{of}\:{a}\:{cyclic}\: \\ $$$${quadrilateral}\:{is}\:{also}\:{cyclic}. \\ $$ Answered by mrW1 last updated on 22/Feb/17 $${ABCD}\:{is}\:{a}\:{convex}\:\:{quadrilateral}. \\…
Question Number 10639 by Saham last updated on 21/Feb/17 $$\mathrm{A}\:\mathrm{manometer}\:\mathrm{wire}\:\mathrm{of}\:\mathrm{lenght}\:\mathrm{60}\:\mathrm{cm}\:\mathrm{is}\:\mathrm{maintained}\:\mathrm{under} \\ $$$$\mathrm{a}\:\mathrm{tension}\:\mathrm{of}\:\mathrm{value}\:\mathrm{20V}\:\mathrm{and}\:\mathrm{an}\:\mathrm{a}.\mathrm{c}\:\mathrm{is}\:\mathrm{passed}\:\mathrm{through} \\ $$$$\mathrm{the}\:\mathrm{wire}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{density}\:\mathrm{of}\:\mathrm{the}\:\mathrm{wire}\:\mathrm{is}\:\mathrm{4000kgm}^{−\mathrm{3}} \:\mathrm{and}\:\mathrm{it}\: \\ $$$$\mathrm{diamerter}\:\mathrm{is}\:\mathrm{2mm}.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{frequency}\:\mathrm{of}\:\mathrm{the}\:\mathrm{a}.\mathrm{c} \\ $$ Commented by Saham last updated on…