Question Number 9896 by caleb last updated on 13/Jan/17 $${l}^{−\mathrm{1}} \left\{\frac{\mathrm{5}{s}^{\mathrm{2}} −\mathrm{21}{s}+\mathrm{30}}{\left({s}−\mathrm{3}\right)\left({s}^{\mathrm{2}} +\mathrm{4}\right)}\right\}\:\:\:{pls}\:{help}\:{solve}\:{this} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9893 by caleb last updated on 13/Jan/17 $${pls}\:{help}\:{me}\:{solve}\:{dis}\:{questiom}\:{it}\:{is}\: \\ $$$${laplace} \\ $$$$ \\ $$$${l}^{−\mathrm{1}} \left\{\frac{\mathrm{4}{s}^{\mathrm{2}} −\mathrm{17}{s}−\mathrm{24}}{\mathrm{5}\left({s}+\mathrm{3}\right)\left({s}−\mathrm{4}\right)}\right\} \\ $$ Terms of Service Privacy Policy…
Question Number 9894 by caleb last updated on 13/Jan/17 $${pls}\:{help}\:{me}\:{solve}\:{dis}\:{questiom}\:{it}\:{is}\: \\ $$$${laplace} \\ $$$$ \\ $$$${l}^{−\mathrm{1}} \left\{\frac{\mathrm{4}{s}^{\mathrm{2}} −\mathrm{17}{s}−\mathrm{24}}{\mathrm{5}\left({s}+\mathrm{3}\right)\left({s}−\mathrm{4}\right)}\right\} \\ $$ Terms of Service Privacy Policy…
Question Number 9880 by sandipkd@ last updated on 12/Jan/17 Answered by bansal22luvi@gmail.com last updated on 12/Jan/17 $${let}\:{the}\:{radius}\:{of}\:{smallest}\:{circle}\:{be}\:{r} \\ $$$${CO}=\left(\mathrm{2}−{x}\right) \\ $$$${C}_{\mathrm{1}} {O}=\left(\mathrm{1}+{x}\right) \\ $$$${C}_{\mathrm{1}} {C}=\mathrm{1}…
Question Number 140941 by mr W last updated on 14/May/21 Commented by mr W last updated on 14/May/21 $${see}\:{Q}\mathrm{140735} \\ $$ Commented by mr W…
Question Number 75376 by TawaTawa last updated on 10/Dec/19 Commented by TawaTawa last updated on 10/Dec/19 $$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$ Answered by 21042004 last updated on…
Question Number 75377 by TawaTawa last updated on 10/Dec/19 Commented by TawaTawa last updated on 10/Dec/19 $$\mathrm{Please}\:\mathrm{see}\:\mathrm{question}\:\mathrm{8}\:\:\mathrm{below}. \\ $$ Commented by TawaTawa last updated on…
Question Number 9813 by tawakalitu last updated on 05/Jan/17 $$\mathrm{From}\:\mathrm{the}\:\mathrm{top}\:\mathrm{of}\:\mathrm{a}\:\mathrm{tower}\:\mathrm{80m}\:\mathrm{high},\:\mathrm{a}\:\mathrm{student} \\ $$$$\mathrm{observe}\:\mathrm{that}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{depression}\:\mathrm{of}\:\mathrm{the}\:\mathrm{top}\: \\ $$$$\mathrm{of}\:\mathrm{a}\:\mathrm{vertical}\:\mathrm{pole}\:\mathrm{A}\:\mathrm{is}\:\mathrm{45}°\:\mathrm{and}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{of}\: \\ $$$$\mathrm{depression}\:\mathrm{of}\:\mathrm{point}\:\mathrm{B}\:\mathrm{on}\:\mathrm{the}\:\mathrm{pole}\:\mathrm{is}\:\mathrm{60}°. \\ $$$$\mathrm{if}\:\mathrm{O}\:\mathrm{is}\:\mathrm{the}\:\mathrm{foot}\:\mathrm{of}\:\mathrm{the}\:\mathrm{pole}\:\mathrm{and}\:\mathrm{OB}\:=\:\mathrm{20m}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}. \\ $$$$\mathrm{leaving}\:\mathrm{your}\:\mathrm{answer}\:\mathrm{in}\:\mathrm{surd}\:\mathrm{form}. \\ $$ Answered…
Question Number 140874 by cherokeesay last updated on 13/May/21 Commented by ok_19 last updated on 13/May/21 $$\mathrm{12}\:\mathrm{cm}^{\mathrm{2}} \\ $$ Answered by mr W last updated…
Question Number 75329 by lalitchand last updated on 10/Dec/19 Answered by $@ty@m123 last updated on 10/Dec/19 $${R}=\frac{{abc}}{\mathrm{4}\bigtriangleup} \\ $$$${where}, \\ $$$$\bigtriangleup=\sqrt{{s}\left({s}−{a}\right)\left({s}−{b}\right)\left({s}−{c}\right)} \\ $$ Terms of…