Question Number 139967 by I want to learn more last updated on 02/May/21 Answered by mr W last updated on 02/May/21 Commented by mr W…
Question Number 139957 by cherokeesay last updated on 02/May/21 Commented by mr W last updated on 02/May/21 $${R}={r}+\frac{\mathrm{2}}{\mathrm{3}}×\sqrt{\mathrm{3}}{r} \\ $$$$\Rightarrow\frac{{R}}{{r}}=\mathrm{1}+\frac{\mathrm{2}\sqrt{\mathrm{3}}}{\mathrm{3}} \\ $$ Commented by Dwaipayan…
Question Number 139840 by mnjuly1970 last updated on 01/May/21 Commented by mnjuly1970 last updated on 01/May/21 $${please}\:{prove}::\Uparrow\Uparrow\Uparrow \\ $$ Answered by mr W last updated…
Question Number 74240 by ajfour last updated on 20/Nov/19 Commented by ajfour last updated on 21/Nov/19 $${Q}.\mathrm{73828}\:\:\:\left({If}\:{each}\:{face}\:{of}\:{outer}\right. \\ $$$${cube}\:{contains}\:{one}\:{corner}\:{of} \\ $$$${inner}\:{cube},\:{find}\:{range}\:{of}\:{s}/{a}. \\ $$$$\left(\boldsymbol{{s}}\:{being}\:{side}\:{length}\:{of}\:{inner}\:{cube},\right. \\ $$$$\left.\:\:{and}\:\boldsymbol{{a}}\:{that}\:{of}\:{outer}.\right)…
Question Number 8685 by Rasheed Soomro last updated on 23/Oct/16 $$\mathrm{Divide}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{in}\:\mathrm{two}\:\mathrm{equal}\:\mathrm{parts} \\ $$$$\mathrm{by}\:\mathrm{drawing}\:\mathrm{an}\:\mathrm{arc}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 139756 by cherokeesay last updated on 01/May/21 Answered by mr W last updated on 01/May/21 Commented by mr W last updated on 01/May/21…
Question Number 8618 by Rasheed Soomro last updated on 18/Oct/16 Commented by Rasheed Soomro last updated on 18/Oct/16 $$\mathrm{AD}\:\:\mathrm{and}\:\:\:\:\mathrm{CD}\:\:\mathrm{are}\:\mathrm{tangents}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{circle}.\:\angle\mathrm{ABC}\:\mathrm{is}\:\mathrm{inscibed}\:\mathrm{angle}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{arc}\:\overset{\frown} {\mathrm{ABC}}\:. \\…
Question Number 74137 by MASANJAJ last updated on 19/Nov/19 Commented by TawaTawa last updated on 19/Nov/19 $$\left(\mathrm{16a}\right) \\ $$$$\:\:\:\:\:\:\mathrm{5}\:\mathrm{painters}\:\mathrm{will}\:\mathrm{spend}\:\mathrm{less}\:\mathrm{hours} \\ $$$$\therefore\:\:\:\:\:\:\:\:\:\mathrm{1}\:\mathrm{painter}\:\:\:=\:\:\mathrm{2}\:×\:\mathrm{6}\:\:=\:\:\mathrm{12}\:\mathrm{hrs} \\ $$$$\therefore\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{5}\:\mathrm{painters}\:\:\:\:=\:\:\:\frac{\mathrm{12}}{\mathrm{5}}\:\mathrm{hrs} \\ $$…
Question Number 8582 by thomas last updated on 16/Oct/16 $$\mathrm{9}×\mathrm{9} \\ $$ Answered by Rasheed Soomro last updated on 17/Oct/16 $$\mathrm{9}×\mathrm{9} \\ $$$$=\left(\mathrm{10}−\mathrm{1}\right)\left(\mathrm{10}−\mathrm{1}\right) \\ $$$$=\left(\mathrm{10}−\mathrm{1}\right)^{\mathrm{2}}…
Question Number 139649 by mnjuly1970 last updated on 30/Apr/21 Commented by mr W last updated on 30/Apr/21 $$\frac{{red}}{{green}}=\frac{\mathrm{6}}{\mathrm{5}} \\ $$ Answered by mr W last…