Question Number 135695 by liberty last updated on 15/Mar/21 $${What}\:{is}\:{the}\:{equation}\:{of} \\ $$$${ellipse}\:{with}\:{center}\:\left(\mathrm{1},−\mathrm{2}\right)\: \\ $$$${excentricity}\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\:,\:{passing} \\ $$$${through}\:\left(\mathrm{2},\:\frac{\mathrm{2}\sqrt{\mathrm{2}}−\mathrm{2}}{\mathrm{3}}\right)\: \\ $$ Answered by mr W last updated on…
Question Number 4612 by Rasheed Soomro last updated on 14/Feb/16 Commented by Rasheed Soomro last updated on 14/Feb/16 $$\:{A}\:\:{triangle}\:{divides}\:\:{its} \\ $$$${circum}-{circle}\:{in}\:{three}\:{arcs} \\ $$$${say}\:\:\boldsymbol{\mathrm{c}}_{\mathrm{1}} ,\boldsymbol{\mathrm{c}}_{\mathrm{2}} ,\boldsymbol{\mathrm{c}}_{\mathrm{3}}…
Question Number 4594 by alimyao last updated on 10/Feb/16 $$\int\mathrm{4}{x}^{\mathrm{2}} \:−\:\frac{\mathrm{5}}{\mathrm{2}{x}^{−\mathrm{2}} }\:+\:\mathrm{4}\:\:{dx},\:{x}\neq\mathrm{0} \\ $$$$ \\ $$ Answered by FilupSmith last updated on 10/Feb/16 $$=\mathrm{4}\int{x}^{\mathrm{2}} {dx}−\frac{\mathrm{5}}{\mathrm{2}}\int{x}^{\mathrm{2}}…
Question Number 70121 by ahmadshahhimat775@gmail.com last updated on 01/Oct/19 Answered by mind is power last updated on 01/Oct/19 $${let}\:{a}\:{angle}\:{left}\:−,{c}\:{side}\:{of}\:{squar} \\ $$$$\Rightarrow{c}=\mathrm{6}{sin}\left({a}\right) \\ $$$$\frac{\mathrm{6}{sin}\left({a}\right)+\mathrm{6}{cos}\left({a}\right)}{{sin}\left(\mathrm{45}\right)}=\frac{\mathrm{10}}{{sin}\left(\mathrm{45}+{a}\right)} \\ $$$$\Rightarrow\mathrm{6}.\left({sin}\left({a}\right)+{cos}\left({a}\right)\right).{sin}\left(\mathrm{45}+{a}\right)=\mathrm{10}{sin}\left(\mathrm{45}\right)…
Question Number 135658 by I want to learn more last updated on 14/Mar/21 Answered by mr W last updated on 15/Mar/21 Commented by mr W…
Question Number 4578 by Rasheed Soomro last updated on 08/Feb/16 $${The}\:{segment}\:{between}\:{the}\:{mid}-{points} \\ $$$${of}\:{two}\:{sides}\:{of}\:{a}\:{triangle}\:{is}\:{parallel} \\ $$$${to}\:{the}\:{third}\:{side}\:{and}\:{half}\:{as}\:{long}.\: \\ $$ Commented by Yozzii last updated on 08/Feb/16 $${Prove}\:{this}\:{theorem}?…
Question Number 4579 by Rasheed Soomro last updated on 08/Feb/16 $${In}\:{a}\:{right}\:{triangle},\:{the}\:{mid}-{point}\:{of}\:{the} \\ $$$${hypotenuse}\:{is}\:{equidistant}\:{from}\:{all}\:{the} \\ $$$${three}\:{vertices}\:{of}\:{the}\:{triangle}. \\ $$ Commented by Yozzii last updated on 08/Feb/16 $${Prove}\:{this}\:{theorem}?…
Question Number 4543 by FilupSmith last updated on 06/Feb/16 $$\mathrm{Triangle}\:{ABC}\:\mathrm{has}\:\mathrm{midpoints} \\ $$$${D},\:{E}\:\mathrm{and}\:{F}. \\ $$$$ \\ $$$$\mathrm{By}\:\mathrm{connecting}\:\mathrm{each}\:\mathrm{verticie}\:\mathrm{with}\:\mathrm{the} \\ $$$$\mathrm{opposite}\:\mathrm{midpoint},\:\mathrm{we}\:\mathrm{create}\:\mathrm{a}\:\mathrm{cress}−\mathrm{section} \\ $$$$\mathrm{called}\:{G}. \\ $$$$ \\ $$$$\mathrm{Prove}\:\mathrm{that}\:\mathrm{all}\:\mathrm{three}\:\mathrm{lines}\:\mathrm{cross}\:\mathrm{at}\: \\…
Question Number 70075 by ajfour last updated on 30/Sep/19 Commented by behi83417@gmail.com last updated on 30/Sep/19 Commented by behi83417@gmail.com last updated on 30/Sep/19 $$\measuredangle\mathrm{ACB}=\frac{\mathrm{540}}{\mathrm{5}}=\mathrm{108}^{\bullet} \\…
Question Number 70048 by TawaTawa last updated on 30/Sep/19 Commented by TawaTawa last updated on 30/Sep/19 $$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$ Commented by Prithwish sen last updated…